Answer:
[OH-] = 10^-1.5 = 0.0316 M
Explanation:
__ KClO₃ → __ KCl + __ O₂
Left Side:
1 K
1 Cl
3 O
Right Side:
1 K
1 Cl
2 O
Since the least common multiple of 3 and 2 is 6, we need to multiply the compound with 2 oxygen by 3 and the compound with 3 oxygen by 2.
This gives us 2KClO₃ → __ KCl + 3O₂.
However, this equation is still not balanced.
Left Side:
2 K
2 Cl
6 O
Right Side:
1 K
1 Cl
6 O
In order to balance the K and Cl, we need to multiply the KCl compound on the right side by 2.
2KClO₃ → 2KCl + 3O₂
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The correct answers :
It increases with a decrease in the concentration of H₂(g).
It decreases with an increase in the concentration of S₂(g).
It decreases with an increase in the concentration of H₂(g).
<h3 /><h3>Further explanation</h3>
Forward reaction : rate to form product
In equilibrium :
The product decreases ⇒ system will move from left to right(forward reaction)
The product increases ⇒ system will move from right to left(reverse reaction)
