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Alika [10]
3 years ago
11

In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to

produce ammonia. The conditions included medium temperature (~500oC), very high pressure (~351kPa), and an iron catalyst. The reaction is represented by the equation: N2(g) + 3H2(g) → 2NH3(g) How many grams of nitrogen are needed to produce 100 grams of ammonia gas?
Chemistry
1 answer:
labwork [276]3 years ago
5 0

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of NH_3 = 100 g

Molar mass of NH_3 = 27 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles

The given balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the given reaction, we conclude that

2 moles of NH_3 produced from 1 mole of N_2

3.7 moles of NH_3 produced from \frac{1mole}{2mole}\times 3.7mole=1.85moles of N_2

Now we have to calculate the mass of N_2.

Mass of N_2 = Moles of N_2 × Molar mass of N_2

Mass of N_2 = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

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Answer:

HCl(aq) + KOH(aq) --> KCl(aq) + H2O(l)

Explanation:

A neutralization reaction is the process between an acid and a base (there are a number of different ways to define acids and bases). An acid is a compound, which dissolves in water by releasing H+ ions, and a base is a compound, which dissolves in water by releasing OH- ions (by Arrhenius' definition, the simplest one). In this case, the neutralization reaction is the process between HCl (hydrochloric acid) - an acid, and KOH (potassium hydroxide) - a base.

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The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane (C8H18) and calculate the mass (
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Explanation:

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Converting 228g of C8H18 to kg, we obtained:

228/1000 = 0.228kg

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Mass of CO2 from the balanced equation = 16 x 44 = 704g

Converting 704g of CO2 to kg, we obtained:

704/1000 = 0.704kg

From the equation,

0.228kg of C8H18 produced 0.704kg of CO2.

Therefore, 1kg of C8H18 will produce = 0.704/0.228 = 3.09kg of CO2

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