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3 years ago

10

Are Constellations based on the magnitude of stars.

2 answers:

salantis [7]3 years ago

8 0

no they are not they are mostly based off roman and Greek Mithos

Nikolay [14]3 years ago

4 0

Constellations are based off of many Greek and Roman fables. Many of their gods and beliefs are pictured in the stars, which is where we get most of our constellations. Hope this helps!

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Name 3-4 objects you use that depend on the electromagnetic spectrum.

iVinArrow [24]

Answer:

3 objects that depend on the electromagnetic spectrum would be television, radios, and the Microwave. This is due to the fact that radio waves depend on the electromagnetic spectrum and televisions and radios require radio waves. The microwaves also depend on the electromagnetic spectrum in order to make the Mircowave work

Explanation:

7 0

3 years ago

Read 2 more answers

A quantity of 1.922 g of methanol (CH3OH) was burned in a constant-volume calorimeter. Consequently,

White raven [17]

Mass of methanol = 1.922g; Change in temperature = 5.14° C; Heat capacity of the bomb calorimeter + water = 8.69kJ/°C. Number of moles.

3 0

2 years ago

What is the velocity of an object that has been in free fall for 1.5s?

Crank

Answer:

D. 15 m/s downward

Explanation:

v = at + v₀

v = (-9.8 m/s²) (1.5 s) + (0 m/s)

v = -14.7 m/s

Rounded to two significant figures, the answer is D, 15 m/s downward.

8 0

3 years ago

A person is drawing water from a well, pulling up a bucket that weighs 4.50 kg, at a constant speed. What is the force exerted o

TEA [102]

Answer:

44.13015

Explanation:

use the 9.8067 newtons to 1 kg conversion

5 0

3 years ago

A certain quantity of steam has a temperature of 100.0 oC. To convert this steam into ice at 0.0 oC, energy in the form of heat

KonstantinChe [14]

Answer:

2452.79432 m/s

Explanation:

m = Mass of ice

$L_s$ = Latent heat of steam

$s_w$ = Specific heat of water

$L_i$ = Latent heat of ice

v = Velocity of ice

$\Delta T$ = Change in temperature

Amount of heat required for steam

$Q_1=mL_s\\\Rightarrow Q_1=m(2.256\times 10^6)$

Heat released from water at 100 °C

$Q_2=ms_w\Delta T\\\Rightarrow Q_2=m4186\times (100-0)\\\Rightarrow Q_2=m0.4186\times 10^6$

Heat released from water at 0 °C

$Q_3=mL_i\\\Rightarrow Q_3=m(333.5\times 10^3)\\\Rightarrow Q_3=m(0.3335\times 10^6)$

Total heat released is

$Q=Q_1+Q_2+Q_3\\\Rightarrow Q=m(2.256\times 10^6)+m0.4186\times 10^6+m(0.3335\times 10^6)\\\Rightarrow Q=3008100m$

The kinetic energy of the bullet will balance the heat

$K=Q\\\Rightarrow \frac{1}{2}mv^2=3008100m\\\Rightarrow v=\sqrt{2\times 3008100}\\\Rightarrow v=2452.79432\ m/s$

The velocity of the ice would be 2452.79432 m/s

6 0

3 years ago