Both the butterfly and the large car will have equal forces but in opposite direction.
<h3>
Newton's third law of motion</h3>
Newton's third law of motion states that action and reaction are equal and opposite. That is, the force exerted on an object is equal to the reaction experienced by the object.
Fa = - Fb
where;
- Fa is the force exerted by the large car
- Fb is the force of the butterfly
Thus, both the butterfly and the large car will have equal forces but in opposite direction.
Learn more about Newton's third law of motion here: brainly.com/question/25998091
#SPJ1
Answer:
a. 5A
b. 39.60%
Explanation:
The computation is shown below:
a. The current does it draw is
= v ÷ R
= 110v ÷ 22
= 5A
b. Now the efficiency of the motor is
n = mgh ÷ vlt
= (10,000 × 9.8 × 8) ÷ (5 × 3600 × 110)
= 784000 J ÷ 1,980,000
= 39.60%
hence, the above formulas are applied & the same is relevant
Answer:
I'm pretty sure it's 20m/s because 1300m divided by 65 seconds is 20 so I think it's 20m/s
Explanation:
Increases
Explanation:
Energy increases the speed of the particles in a substance. When energy is added to a substance they gain more kinetic to move.
- When energy is added to solid, the particles begins to vibrate about their fixed point.
- They reach a point where they break lose and the ordered structure of a typical solid collapses.
- They begin to move about freely and flow as in a liquid.
- When enough energy is added, they break their intermolecular attractions and becomes gaseous.
- An increase in energy increases the kinetic energy of the particles of a substance.
- The reverse is the case when energy is removed.
Learn more:
Kinetic energy brainly.com/question/6536722
#learnwithBrainly
Answer:
0.1 m
Explanation:
The closest distance the electrodes used in an NCV test in oerder to measure
the voltage change as a response to the stimulus is 0.1 m.
This is because the shortest observable time period is not less than the action-potential time response of 1 mili second the length traveled by the sensation during this time is 1 m sec x 100 m / s =0.1 m, which is the shortest distance the electrodes could be positioned on the nerve.
