Question

What is the value of n in the equation 32 × 33 = 3n?

Answer 1

Answer:

5

Step-by-step explanation:

u can add 2 and 3 when their base number (3) are the same

Answer 2

Answer: The value of $n$ is 5

Step-by-step explanation:

-Solve:

$3^2$ × $3^3$ $=3^n$

-If two numbers with exponents are multiplying together, then the exponents would add up together:

$3^5 = 3^n$

-Simplify by the exponent:

$243 = 3^n$

-Take the logarithm both sides of the equation:

$log(3^n)= log (243)$

- Then, you divide both sides by $log (3)$ :

$n=\frac{log(243)}{log(3)}$

- Use the change-of-base formula, which is $\frac{log(a)}{log(b)} = log_{b}(a)$:

$n = log_{3}(243)$

$n = 5$

So, the value of $n$ is 5.