<h2>
Answer: 13985.4 g</h2>
Explanation:
Mass = volume × density
Mass = 652 cm³ × 21.45 g/cm³
= 13985.4 g
Explanation:
<span>The mass of an atom located in the A) nucleus.</span>
Answer:
FV = $3506.112
Interest = $506.112
Explanation:
We are given;
Annual deposit; A = $1000
Interest rate; i = 8% = 0.08
Number of years; n = 3
The value of the annuity after 3 years will be gotten from the formula;
FV = A[((1 + i)ⁿ - 1)/i](1 + i)
FV = 1000(((1 + 0.08)³ - 1)/0.08)(1 + 0.08)
FV = 1000(1.08⁴ - 1.08)/0.08
FV = $3506.112
Since you deposited $1000 each year, then after 3 years, total deposited = 3 × 1000 = $3000
Since FV = $3506.112, then interest = $3506.112 - $3000
Interest = $506.112
A - Endothermic. This is because it absorbs heat rather than releases it.
B - Exothermic. It's releasing heat which in turn makes the beaker hot.
C - Endothermic. The Ammonium Chloride is absorbing the heat away from the beaker.
D - Exothermic. To produce nuclear energy, it needs to release heat.
E - Endothermic. The hydrogen and oxygen atoms are absorbing the heat given off from the electric current.
F - Exothermic. It is producing heat or releasing heat.
Exothermic is the losing, release, or production of heat. Endothermic is the exact opposite; it is the storing of heat.
Hope this helps!
To know the electrostatic force between two charges or between two ions, you can use the Coulomb's Law. The equation is F = k*q1*q1/r^2, where F is the electrostatic force, q1 and q2 are the charger for Na and Cl, and r is the distance between the centers of both atoms. In literature, the distance is 0.5 nm or 0.5 x 10^-9 meters. The charge for Na+ and Cl- is the same magnitude but different in sign. Since Na+ is a cation, its charge is +1.603x10^-19 C (the charge of an electron). For Cl- being an anion, its charge is -1.603x10^-19 C. The constant k is an empirical value equal to 9x10^9. Using the formula:
F = (9x10^9)(+1.603x10^-19)(-1.603x10^-19)/(0.5 x 10^-9)^2
F = -9.25 x 10^-10 Newtons
The negative denotes that the net force is more towards the Cl- ion.
