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tiny-mole [99]
3 years ago
8

Which element is a Nobal gas

Chemistry
1 answer:
drek231 [11]3 years ago
5 0

Answer:

A. Helium

Explanation:

In chemistry, a noble gas refers to a group of elements placed in group 18, which is located in the last column from left to right in the periodic table. Additionally, these elements are defined by their low reactivity, also as gases, they do not have color or odor. Helium is part of this group that contains other 5 elements because Helium characteristics are similar to other noble gases, indeed this is the first noble gas in the periodic table. Additionally, helium is an abundant element found in all the universe especially in stars. Thus, the element that is a noble gas is Helium.

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Airida [17]
<span>The solute is the substance that is being dissolved while the solvent is the base that the solute is bring dissolved in. For example, in salt water, salt would be the solute that dissolves into the water, and the water is the solvent that the salt is being dissolved in.</span>
4 0
3 years ago
Nitric Oxide gas react to form nitrogen dioxide as shown in the following reaction:
Zina [86]

Answer:

2 moles of NO2 would be produced.

Explanation:

Here, you will have to do a mole to mole ratio.

2 moles NO x (2 moles NO2 / 2 moles NO)

= 2 moles NO2

6 0
3 years ago
She dissolves a 10.0mg sample in enough water to make 30.0mL of solution. The osmotic pressure of the solution is 0.340torr at 2
uranmaximum [27]

Answer:

(a)The molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol

(b)The freezing point for the aqueous solution is -3.413\times10^{-5} C

Explanation:

The osmotic pressure (π) is given by the following equation:

\pi =cRT

c= Concentration of solution

R = universal gas constant = 62.364 \frac{L\times torr}{mol\times K}

T = temperature

Weight of solute = w = 10.0 mg

Let the molecular weight of the solute be m g/mol.

Concentration = c=\frac{n}{V}\\ n=\frac{w}{m}\\ n=\frac{10\times10^{-3}}{m}\\c=\frac{10\times10^{-3}}{m\times30\times10^{-3}}M

m=\frac{RT}{3\pi}

m = 18220.071g/mol

Therefore, the molar mass of the gene fragment is 18220.071g/mol = 18.22 kg/mol

\Delta T_{f}=K_{f}m

m is the molality of the solution.

m = 1.835\times10^{-5} mol/kg

\Delta T_{f}=1.86\times m

\Delta T_{f} = 3.413\times10^{-5} C

The freezing point for the aqueous solution is -3.413\times10^{-5} C

8 0
3 years ago
The reusable booster rockets of the space shuttle use a mixture of aluminum and ammonium perchlorate as fuel. A possible reactio
Nuetrik [128]

ΔH for this reaction : -2668.4 (exothermic)

<h3>Further explanation  </h3>

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)  

The value of ° H ° can be calculated from the change in enthalpy of standard formation:  

∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants)  

you can search the value of ΔHf on the internet

∆H ° rxn =( ∆H Al₂O₃+∆H AlCl₃+3.∆H NO + 6.∆H H₂O)-(∆H Al+∆H NH₄ClO₄)

\tt \Delta H^o~rxn=(-1669.8+-704+(3\times 90.4)+(6.\times -241.8)-(3\times 0+3\times  -295)\\\\\Delta H6o~rxn=-3553.4+885=-2668.4~kJ/mol

8 0
3 years ago
Categorize each hydrocarbon as being saturated or unsaturated.
Bond [772]

Answer :

Saturated hydrocarbon : 3-methyloctane, propane, heptane.

Unsaturated hydrocarbon : cyclopentene, heptyne

Explanation :

Saturated hydrocarbon : These are those hydrocarbons in which all carbon atoms and hydrogen atoms are bonded together with single bonds.

For example : Methane, Ethane, etc.

Unsaturated hydrocarbon : These are those hydrocarbons in which carbon-carbon atom bonded together with double or triple covalent bonds.

For example : Ethene, Butyne, etc.

Therefore, the saturated and unsaturated hydrocarbons are:

Saturated hydrocarbon : 3-methyloctane, propane, heptane.

Unsaturated hydrocarbon : cyclopentene, heptyne

8 0
3 years ago
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