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Rasek [7]
2 years ago
15

Please help with this algebra ii question

Mathematics
2 answers:
algol132 years ago
5 0
B


Mark brainliest please


Hope this helps you
Veronika [31]2 years ago
4 0

Answer:

Second Choice

Step-by-step explanation:

The vertex form can be expressed as:

\displaystyle \large{f(x) = a {(x - h)}^{2}  + k}

We know that the vertex is (h,k) which we are given (-3,-1). Substitute h = -3 and k = -1 in:

\displaystyle \large{f(x) = a {(x - ( - 3))}^{2}   - 1} \\  \displaystyle \large{f(x) = a {(x  + 3)}^{2}   - 1}

Now we know that the parabola passes through (-2,1). Substitute x = -2 and f(x) = 1 then solve for a.

\displaystyle \large{1= a {( - 2 + 3)}^{2}   - 1} \\   \displaystyle \large{1= a {(1)}^{2}   - 1} \\  \displaystyle \large{1= a - 1}  \\   \displaystyle \large{1 + 1= a } \\   \displaystyle \large{2 = a}

Therefore a = 2.

Hence:-

\displaystyle \large{f(x) = 2{(x  + 3)}^{2}   - 1}

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Can someone help me on this question
dexar [7]
It’s an obtuse triangle, this is because none of the sides/angles are equal to one another. Hope this helped you
3 0
3 years ago
At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special. There are 5 c
Tju [1.3M]

Answer: 35

Step-by-step explanation:

Given : At Deb’s Deli, a customer may choose either a sandwich and a salad or a sandwich and a soup for the lunch special.

The number of choices for sandwiches = 5

The number of choices for salad = 4

The number of choices for soup = 3

Now, the number of  possible lunch special combinations can be ordered will be :-

5\times4+5\times3=20+15=35

Hence, the number of  possible lunch special combinations can be ordered will be 35.

3 0
3 years ago
Third question I'm giving 50 points ​
marishachu [46]

Answer:   B

Step-by-step explanation:

y = mx + mc

The perpendicular will have slope -1/m and intercept mc, which is

y = (-1/m)x + mc

For the answers you have to factor out a -1/m from both terms:

$y = -\frac 1m x + mc \cdot -m \cdot -\frac 1m$\\

$y = -\frac 1m (x + mc \cdot -m)$

$\boxed{\;\textbf{(B)}\ \,y = -\frac 1m (x - m^2 c)\;}$

5 0
2 years ago
If 1,529 students participate in field day, how many cases of water bottles should be purchased if the water comes in cases of 1
serious [3.7K]
Dude that’s easy hahahahhahaha
6 0
3 years ago
Hey can someone please help explain and answer this 1 question. There's a picture. Thank you!
g100num [7]
We'll first clear a few points.
1. A hyperbola with horizontal axis and centred on origin (i.e. foci are centred on the x-axis) has equation
x^2/a^2-y^2/b^2=1
(check: when y=0, x=+/- a, the vertices)
The corresponding hyperbola with vertical axis centred on origin has equation
y^2/a^2-x^2/b^2=1
(check: when x=0, y=+/- a, the vertices).

The co-vertex is the distance b in the above formula, such that 
the distance of the foci from the origin, c satisfies c^2=a^2+b^2.
The rectangle with width a and height b has diagonals which are the asymptotes of the hyperbola.

We're given vertex = +/- 3, and covertex=+/- 5.
And since vertices are situated at (3,0), and (-3,0), they are along the x-axis.
So the equation must start with
x^2/3^2.

It will be good practice for you to sketch all four hyperbolas given in the choices to fully understand the basics of a hyperbola.
6 0
3 years ago
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