Answer:-
10.0
Explanation: -
The equation is
N2O4 = 2NO2.
Concentration of NO2 = [NO2} = 0.500 M
Concentration of N2O4 = [N2O4] = 0.0250 M
Keq is the equilibrium constant.
It is the ratio of the concentration of products raised to the stoichiometric coefficient of the product to the concentration of the reactants raised to the stoichiometric coefficient of the reactants.
The expression for Keq = [NO2] ^2 / [N2O4]
= 0.500^2 / 0.0250
= 10.0
Answer:
Part A
HCOOH(aq) + NaOH(aq) → HCOONa(aq) + H2O(l)
Part B
ClCH2CH2CO2H(aq) + NaOH(aq) ------> ClCH2CH2CO2Na(aq) + H2O(l)
Explanation:
The reaction between an alkanoic acid and a base is a neutralization reaction. The reaction occurs as follows;
RCOOH + NaOH ----> RCOONa + H2O
We have to note the fact that the net ionic reaction still remains;
H^+(aq) + OH^-(aq) ---> H2O(l)
In both cases, the reaction can occur and they actually do occur as written.
Answer:
you could've googled it but here.
Explanation:
The former OSHA limit for sodium hydroxide (also known as caustic soda or Iye) was 2 mg/m3 as an 8-hour TWA. OSHA proposed a 2-mg/m3 ceiling limit for sodium hydroxide, based on the ACGIH- and NIOSH-recommended limits.
KE=6,250Joules
You plug in your given numbers and remember to square 5 because that’s the speed
