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3 years ago

An oxide of arsenic contains 3.26 g of arsenic and 1.04 g of oxygen. What is the empirical formula for this oxide?

Chemistry

1 answer:

Delvig [45]3 years ago

6 0

The empirical formula for this oxide : As₂O₃

Further explanation:

Given

mass of Arsenic=3.26 g

mass of Oxygen = 1.04 g

Required

The empirical formula

Analysis

find mole of elements
determine the ratio of each element

Solution

mol of Arsenic(MW=74,9216 u) :

$\tt mol=\dfrac{3.26}{74,9216}=0.0435$

mol of Oxygen(MW=15.999 u) :

$\tt mol=\dfrac{1.04}{15.999}=0.065$ .

The ratio for each element (divide by smaller mol⇒Arsenic)

Arsenic : Oxygen :

$\tt \dfrac{0.0435}{0.0435}\div \dfrac{0.065}{0.0435}=1\div 1.5\rightarrow 2\div 3$

The empirical formula : As₂O₃

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1 year ago

How many equivalents are present in 10 g of Ca2+? 1 0.5 1.5 2

Lynna [10]

0.5

Explanation:

Given parameters:

Mass of Ca²⁺ = 10g

unknown:

Equivalent weight = ?

Solution:

Equivalent weight that is the amount of electrons which a substance gains or loses per mole.

Ca²⁺ has +3 charge

It lost 2e⁻;

therefore;

In 1 mole of Ca²⁺, we have 2 equivalent weight

1 mol Ca²⁺ = 2eq. wts.

1 mol Ca x (40 g / 1 mol ) x (1 mol / 2 eq.wts.) = 20.0 g = 1 eq.wt.

Therefore;

10.0 g Ca²⁺ x (1 eq.wt. / 20.0 g) = 0.5 eq.wts.

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3 years ago

Mercury has an atomic mass of 200.59 amu. calculate the mass of 3.0 x 10^10 atoms

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To determine mass of the given number of atoms of mercury, we need a factor that would relate the number of atoms to number of moles. In this case, we use the Avogadro's number. It is a number that represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. The number of units could be atoms, molecules, ions or electrons. To convert into mass, we use the given amu of mercury since it is equal to grams per mole. We calculate as follows:

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3 years ago

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maksim [4K]

Answer:

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Explanation:

HF = 1.62g

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To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:

Kc = [H₃O⁺] [F⁻] / [HF]

Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:

[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M

[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M

[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M

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