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Rina8888 [55]
2 years ago
15

An oxide of arsenic contains 3.26 g of arsenic and 1.04 g of oxygen. What is the empirical formula for this oxide?

Chemistry
1 answer:
Delvig [45]2 years ago
6 0

The empirical formula for this oxide : As₂O₃

Further explanation:

Given

mass of Arsenic=3.26 g

mass of Oxygen = 1.04 g

Required

The empirical formula

Analysis

  • find mole of elements
  • determine the ratio of each element

Solution

mol of Arsenic(MW=74,9216 u) :

\tt mol=\dfrac{3.26}{74,9216}=0.0435

mol of Oxygen(MW=15.999 u) :

\tt mol=\dfrac{1.04}{15.999}=0.065.

The ratio for each element (divide by smaller mol⇒Arsenic)

Arsenic : Oxygen :

\tt \dfrac{0.0435}{0.0435}\div \dfrac{0.065}{0.0435}=1\div 1.5\rightarrow 2\div 3

The empirical formula : As₂O₃

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Answer:

The pH is 1.08,  being an acid pH

Explanation:

pH is a parameter used to measure the degree of acidity or alkalinity of a substance. The pH scale ranges from 0 to 14. Values ​​less than 7 indicate the acidity range and those greater than 7 indicate alkalinity or basicity. Value 7 is considered neutral. Mathematically, pH is the negative logarithm of the molar concentration of hydrogen or proton ions (H⁺) or hydronium ions (H₃O⁺).

pH= - log [H⁺]= - log [H₃O⁺]

A strong acid is an acid that completely dissociates into hydrogen ions and anions in solution. This implies that the initial concentration of acid is equal to the final concentration of H₃O⁺. This occurs with acid HCl.

So,  pH is calculated as:

pH= - log (0.083)

pH= 1.08

<u><em>The pH is 1.08,  being an acid pH</em></u>

8 0
3 years ago
Which statement is true about intermolecular forces?
seropon [69]

Answer:

Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.

Importance:

Intermolecular forces are important because they determine the physical properties of substances. Many of the life-sustaining properties of water such as its high heat capacity are a result of the hydrogen bonding capabilities it has and are thus due to intermolecular forces.

4 0
2 years ago
Which two of Earth's spheres interact when the rainfall in a region increases after a volcanic eruption?
motikmotik

Answer:

Geosphere and hydrosphere is the correct answer to the given question .

Explanation:

The Volcanic eruption substances alter ecosystems and create pollutants and gasses in the environment as well as in the waters.The Volcanic eruption is effected the climate as well as the weather of the environment system .The volcanic eruption is simply effected the rainfall of the climate environment.

  • The Geosphere and hydrosphere communicate when the amount of rain rises in the region of the following a volcanic eruption.
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7 0
3 years ago
Read 2 more answers
What is the mass of 5 mole of ammonia . Calculate the number of NH₃ molecules, nitrogen atom and hydrogen atoms in it..
Aloiza [94]

Molar mass of NH_3

\\ \sf\longmapsto 14u+3(1u)

\\ \sf\longmapsto 14u+3u

\\ \sf\longmapsto 17g/mol

We know.

No of moles=Given mass/Molar mass

\\ \sf\longmapsto Given\;Mass=17(5)

\\ \sf\longmapsto Given \:Mass\:of\:NH_3=85g

Now

Lets write the balanced equation

\\ \sf\longmapsto N_2+3H_2=2NH_3

  • There is 2moles of Ammonia
  • 3moles of H_2
  • 1mole of N_2

Now

\boxed{\sf No\:of\:Molecules =No\:of\;moles\times Avagadro\:no}

For Hydrogen

\\ \sf\longmapsto 3\times 6.023\times 10^{23}

\\ \sf\longmapsto 18.069\times 10^{23}

\\ \sf\longmapsto 1.8\times 10^{22}molecules

For Ammonia

\\ \sf\longmapsto 2\times 6.023\times 10^{23}

\\ \sf\longmapsto 12.046\times 10^{23}

\\ \sf\longmapsto 1.2\times 10^{22}molecules

For Nitrogen

\\ \sf\longmapsto 1\times 6.023\times 10^{23}

\\ \sf\longmapsto 6.023\times 10^{23}molecules

3 0
2 years ago
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Answer: 1.27 bar

Explanation:

1 atm = 1.01325 bar

1.25 atm = Z (let Z be the unknown value)

To get the value of Z, cross multiply

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1 atm•Z = 1.2665625 atm•bar

To get the value of Z, divide both sides by 1 atm

1 atm•Z/1 atm = 1.2665625 atm•bar/1atm

Z = 1.2665625 bar

(Round up Z to the nearest hundredth as 1.27 bar)

Thus, 1.25 atm when coverted gives 1.27 bar

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