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astraxan [27]
2 years ago
5

Look at the following chemical compounds. State how many molecules of each reactant are present. (I’m sorry I’ve been working on

this forever please help me)
A. NaOH.

Na___ O____ H____

B. CO2.

C____ O_____

C. 3CaO.

Ca____ O_____

D. 2MgCl2.

Mg ____ Cl____
Chemistry
1 answer:
Kryger [21]2 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

<h3>Compound ~ \mathrm{NaOH}</h3>

Na = 1

O = 1

H = 1

<h3>Compound ~ \mathrm{CO_2}</h3>

C = 1

O = 2

<h3>Compound ~ \mathrm{3  \: CaO}</h3>

Ca = 3

O = 3

<h3>Compound ~ \mathrm{2 MgCl_2}</h3>

Mg = 2

Cl = 4

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Answer:

During cellular respiration, plants take in carbon dioxide from the air and break down stored glucose.

Explanation:

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Calculate the pH during the titration of 20.00 mL of 0.1000 M dimethylamine, (CH3)2NH(aq), with 0.1000 M HCl(aq) after 21.23 mL
Evgesh-ka [11]

The pH value of the solution is mathematically given as

pH=2.35

<h3>What pH value of the solution?</h3>

Question Parameters:

pH during the titration of 20.00 mL of 0.1000 M dimethylamine,

with 0.1000 M HCl(aq) after 21.23 mL of the acid

Generally, the equation for the  Chemical Reaction  is mathematically given as

(CH3)2NH(aq), +Hcl   ---> <---- (CH3)2NH2Cl(aq)

Therefore

HCl=\frac{0.186mol}{41.86}

HCL=0.00444M

WHere

HClaq--->H+(aq)+Cl-(aq)

Hence

H+=0.00444M

pH= -log{H+}

pH=log(0.00444)

pH=2.35

For more information on Chemical Reaction

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True or False. A force is a push or pull exerted on an object.
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TRUE

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A 45ml of a 4M solution of CaBr2 contains how many grams of CaBr2?
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The required mass of calcium bromide is 35.98 grams.

<h3>What is molarity?</h3>

Molarity is any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V, where

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Moles will be calculated by using the above equation as:

n = (4)(0.045) = 0.18 mole

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

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Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g

Hence required mass of CaBr₂ is 35.98 grams.

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