Answer: 45.983 g CBr₄
Explanation:
To convert from moles to grams, you know that we will need molar mass and Avogadro's number.
Avogadro's number: 6.022×10²³ molecules/mol
Molar mass: 331.627 grams/mol
Now that we have what we need, you can use these to solve for grams. 
Our final answer is 45.983 g CBr₄.
It would be: c/∧ = 3*10^8 / 4.25*10^-11 = 7.05 * 10^18 /s...
13.0/18=.07222222
sig figs: 0.722 mole of water
Answer:
should be Anaerobic Digestion
Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1 . Because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.