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3 years ago

Calculate the mass of potassium sulphate required to prepare its 10% solution in 100g water.

Chemistry

1 answer:

Paul [167]3 years ago

3 0

Answer:

The mass of Potassium Sulphate required to prepare its ten percent(10%) solution in hundred gram(100g) of water is 11.11g. Explanation: Formula: mass of solute/mass of solution×100; A 10% mass solution in 100g of water means x/(100 + x) = 1/10 where x = mass required.

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Why is boiling water a physical change

Harrizon [31]

Answer:

Boiling water is an example of a physical change and not a chemical change because the water vapor still has the same molecular structure as liquid water (H2O).

Explanation:

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3 years ago

Calculate the wavelength of the photon that would be absorbed or emitted. Round your answer to 3 significant digits.

Flauer [41]

This is an incomplete question, the image for the given question is attached below.

Answer : The wavelength of photon would be absorbed, $3.06\times 10^{-7}m$

Explanation :

From the given diagram of energy we conclude that,

Energy at ground state, A = 400 zJ

Energy of 2nd excited state, C = 1050 zJ

Now we have to calculate the energy of the photon.

$E=E_c-E_A$

$E=(1050-400)zJ= 650zJ=650\times 10^{-21}J$

Now we have to calculate the wavelength of the photon.

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

E = energy of photon = $650\times 10^{-21}J$

$\nu$ = frequency of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength of photon = ?

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$650\times 10^{-21}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}$

$\lambda=3.06\times 10^{-7}m$

Therefore, the wavelength of photon would be absorbed, $3.06\times 10^{-7}m$

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3 years ago

What are the three major branches of natural science?

Shtirlitz [24]

Physical science , earth science,and life science are the branches of natural science

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3 years ago

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A galvanic cell consists of a Cu(s)|Cu2+(aq) half-cell and a Cd(s)|Cd2+(aq) half-cell connected by a salt bridge. Oxidation occu

Kryger [21]

Answer:

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

Explanation:

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The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

As it is given that cadmium acts as anode, it must be on the left hand side and copper must be on right hand side.

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

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3 years ago

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Nataliya [291]

Elements are substances that contain only 1 kind of atom.

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3 years ago

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