Answer:
id be scared because this thing is moving by its self at an alarming rate
Explanation:
Answer:
The electric force on q₁ is
.
Explanation:
Given that,
Charge on ![q_{1}=-6.0\ \mu C](https://tex.z-dn.net/?f=q_%7B1%7D%3D-6.0%5C%20%5Cmu%20C)
Distance ![x= -3.0\ m](https://tex.z-dn.net/?f=x%3D%20-3.0%5C%20m)
Charge on
at origin
Distance ![x= 3.0\ m](https://tex.z-dn.net/?f=x%3D%203.0%5C%20m)
Charge on ![q_{3}=-1.0\ \mu C](https://tex.z-dn.net/?f=q_%7B3%7D%3D-1.0%5C%20%5Cmu%20C)
We need to calculate the electric force on q₁
Using formula of electric force
![F_{12}=\dfrac{kq_{1}q_{2}}{r^2}](https://tex.z-dn.net/?f=F_%7B12%7D%3D%5Cdfrac%7Bkq_%7B1%7Dq_%7B2%7D%7D%7Br%5E2%7D)
Put the value into the formula
![F_{12}=\dfrac{9\times10^{9}\times(-6.0\times10^{-6})\times1.0\times10^{-6}}{(3.0)^2}](https://tex.z-dn.net/?f=F_%7B12%7D%3D%5Cdfrac%7B9%5Ctimes10%5E%7B9%7D%5Ctimes%28-6.0%5Ctimes10%5E%7B-6%7D%29%5Ctimes1.0%5Ctimes10%5E%7B-6%7D%7D%7B%283.0%29%5E2%7D)
![F_{12}=-0.006\ N](https://tex.z-dn.net/?f=F_%7B12%7D%3D-0.006%5C%20N)
Negative sign shows the attraction force.
We need to calculate the electric force F₁₃
![F_{13}=\dfrac{9\times10^{9}\times(-6.0\times10^{-6})\times(-1.0\times10^{-6})}{(6.0)^2}](https://tex.z-dn.net/?f=F_%7B13%7D%3D%5Cdfrac%7B9%5Ctimes10%5E%7B9%7D%5Ctimes%28-6.0%5Ctimes10%5E%7B-6%7D%29%5Ctimes%28-1.0%5Ctimes10%5E%7B-6%7D%29%7D%7B%286.0%29%5E2%7D)
![F_{13}=0.0015\ N](https://tex.z-dn.net/?f=F_%7B13%7D%3D0.0015%5C%20N)
Positive sign shows the repulsive force.
We need to calculate the net electric force
![F=F_{12}+F_{13}](https://tex.z-dn.net/?f=F%3DF_%7B12%7D%2BF_%7B13%7D)
![F=-0.006+0.0015](https://tex.z-dn.net/?f=F%3D-0.006%2B0.0015)
![F=0.0045\ N](https://tex.z-dn.net/?f=F%3D0.0045%5C%20N)
![F=4.5\times10^{-3}\ N](https://tex.z-dn.net/?f=F%3D4.5%5Ctimes10%5E%7B-3%7D%5C%20N)
Hence, The electric force on q₁ is
.
Answer:
E=mc2
Explanation:
It explains that in their interiors, atoms fuse together, creating energy.
The total electric potential will be 4.50 ×10⁴ V. The potential difference is the difference in electric potential between two charged substances.
<h3>What is the electrical potential difference?</h3>
The amount of work performed in an electrical field to move a unit charge from one location to another is defined as the electrical potential difference.
The distance between all charges and the center is the same. The 10,500 mC, 11.50 mC, 21.00 mC, and 20,500 mC charges neglect each other's potentials.
Hence, the total electric potential will be 4.50 ×10⁴ V.
To learn more about the electric potential difference, refer to the link;
brainly.com/question/9383604
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