The weight of an object is the force of gravity between Earth's
mass and the object's mass.
The forces of gravity always come in equal, opposite pairs.
The Earth's weight on the object is the same as the object's
weight on the Earth, and when the object falls to Earth, Earth
falls to the object.
When a force applied to a breaker bar the torque can be calculated by multiplying the<u> length of the lever</u> by the tangential component of force on the lever.
<h3>What is torque?</h3>
Torque is the <u>rotating equivalent</u> of force in physics and mechanics. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect. It illustrates how a force can cause a change in the body's rotational motion.
Torque is given by the formula :
α = r x F ( bold letters represent vector quantities)
The S.I. unit for torque is : N - m ( Newton - meter)
<h3>How do we define 1 N-m of torque?</h3>
The newton-metre is a torque unit (also known as a moment) in the SI system. The torque produced by a one newton force applied <u>perpendicularly to the end of a one metre long</u> moment arm is known as a newton-metre.
To learn more about torque:
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Answer:
12.6 cm
Explanation:
We can use the mirror equation to find the distance of the image from the mirror:
where here we have
f = 9.50 cm is the focal length
p = 39 cm is the distance of the object from the mirror
Solving the equation for q, we find:
Answer:
The friction force is 250 N
Explanation:
The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):
In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:
(1)
We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:
- the pull, forward, F = 250 N
- the friction force, backward, 
Given (1), we have
So the force of friction must be equal to the pull:
