A 1569 kg car moves with a velocity of 15 m/s. What is its kinetic energy? Joules

A solid object has a density of 0.75 g/mL, in which liquid(s) will it sink? SUPPORT your answer.

sukhopar [10]

The object will sink in any liquid whose density is less than 0.75 g/mL .

A few examples are butane, ether, gasoline, hexane, octane, naphtha, pentane, and propane.

3 0

3 years ago

suppose you need to design a parachute system to help a remote camera land safely at the bottom of a cave. the camera will drop

Marina86 [1]

The answer is hang glider.

<h3>What is the model?</h3>

In high school, I created a project for a similar experiment that was accepted.

It matters what you carry the egg in because it is an egg, so something cushioned.

Use the fabric and cut the paper bag to make the kind of parachute I mentioned before.

When people go sky divining, they use a specific kind of parachute because the design is supposed to slow the fall and give them a chance to make a safe landing.

To learn more about hang glider, refer

brainly.com/question/2374318

#SPJ4

3 0

1 year ago

A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.

snow_lady [41]

Complete Question

A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.38 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.)

Answer:

The velocity is $v = 3.79 *10^{5} \ m/s$

Explanation:

From the question we are told that

The magnitude of the electric field is $E = 144 \ kV /m = 144*10^{3} \ V/m$

The magnetic field is $B = 0.38 \ T$

The force due to the electric field is mathematically represented as

$F_e = E * q$

and

The force due to the magnetic field is mathematically represented as

$F_b = q * v * B * sin(\theta )$

Now given that it is perpendicular , $\theta = 90$

=> $F_b = q * v * B * sin(90)$

=> $F_b = q * v * B$

Now given that it is not deflected it means that

$F_ e = F_b$

=> $q * E = q * v * B$

=> $v = \frac{E}{B }$

substituting values

$v = \frac{ 144 *10^{3}}{0.38 }$

$v = 3.79 *10^{5} \ m/s$

7 0

2 years ago

The intensity level of a "Super-Silent" power lawn mower at a distance of 1.0 m is 100 dB. You wake up one morning to find that

Gala2k [10]

Answer:

The intensity level in the room is 63 dB

Explanation:

To calculate the intensity of sound in the room, we use the equation of definition of decibels

β = 10 log (I / Io) (1)

With “I” the sound intensity and “Io” the threshold intensity 1.0 10⁻⁻¹² W/m²

To calculate the intensity we will use the initial data and remember the power of the emitted sound is constant, in addition that the sound propagates in three-dimensional form or on a spherical surface

I = P/A ⇒ P = I A

The area of a sphere is 4 π r², where I can calculate of 1

β/10 = log (I/Io)

I / Io = ${10}^{\beta /10}$

I = Io ${10}^{\beta /10}$

I = 1 10⁻¹² 10⁽¹⁰⁰/¹⁰⁾ = 1 10⁻¹² 10¹⁰

I = 1.0 10⁻² W

With this we can calculate the intensity for a distance of 20 m

I = 1.0 10⁻² / ( 4π 20²)

I = 2.0 10⁻⁶ W/m²

We have already found the intensity at the point of interest, so we can calculate the intensity in decibels at this point with equation 1

β = 10 log(2.0 10⁻⁶ / 1.0 10⁻¹²)

β = 10 log ( 2 10⁶) = 10 6.3

β = 63 dB

The intensity level in the room is 63 dB

5 0

3 years ago

Star meaning plz :) I need help

Mamont248 [21]

a fixed luminous point in the night sky which is a large, remote incandescent body like the sun. or a conventional or stylized representation of a star, typically one having five or more points.

7 0

2 years ago