The speed at which a light aircraft can take off is 120 km/h. (A) What is the minimum constant acceleration required for the pla ne to take off after it has run 240 meters? (B)How long does it take to take off? Ps. I want a solution. For reference, The answer is ..(a)2.32m/s^2 (b) 14.4s
1 answer:
Answer:
A) a = 2.31[m/s^2]; B) t = 14.4 [s]
Explanation:
We can solve this problem using the kinematic equations, but firts we must identify the data:
Vf= final velocity = take off velocity = 120[km/h]
Vi= initial velocity = 0, because the plane starts to move from the rest.
dx= distance to run = 240 [m]
To find the time we must use another kinematic equation.
You might be interested in
1. Centimeter 2. Kilogram 3. Millisecond 4. DL 5. Kg 6. Mm 7. S 8. Mm 9. Us
You would have to put the number together
Answer:
Yes it is better to pull the rope rather than push it
Explanation:
Let the force is applied at an angle of 60 degree
so we will have net vertical force on the crate is given as
here we know
now friction force on the crate is given as
Yes it is better to pull the rope rather than push it
Answer:
tqm-apwk-wix
join join
Force = 9x10^9 x (6x10^-7 x 6x 10^-7) / (.5)^2 = 0.013 N Using the formula; F = 9x10^9 x (Q1 x Q2) / r^2