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Natalka [10]
3 years ago
11

Heat transfer within a fluid takes place by

Physics
1 answer:
lilavasa [31]3 years ago
3 0
I think its b not sure
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I’m between radiant energy to mechanical and kinetic energy to mechanical
Rama09 [41]
The energy in wind CAME from radiant energy originally, but it isn't
radiant energy any more.  It's the energy in the mass of moving air,
and that's KINETIC energy.

You could move the turbine blades with stones or pingpong balls,
push the blades with your hands, or shoot water at them from a hose. 
In any case, you'd have moving mass with kinetic energy transfer that
energy to the turbine.  A moving mass of air does the same thing.
4 0
3 years ago
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The Force of friction between an object and the surface upon which it is sliding is 12N. The weight of the object is 20N. What i
shtirl [24]

Answer: The coefficient of kinetic friction is μ = 0.6

Explanation:

For an object of mass M, the weight is:

W = M*g

where g is the gravitational acceleration: g = 9.8m/s^2

And the friction force between this object and the surface can be written as:

F = W*μ

where μ is the coefficient of friction (kinetic if the object is moving, and static if the object is not moving, usually the static coefficient is larger)

In this case, the weight is:

W = 20N

And the friction force is:

F = 12N

Replacing these values in the equation for the friction force we get:

12N = 20N*μ

(12N/20N) = μ = 0.6

The coefficient of kinetic friction is μ = 0.6

7 0
3 years ago
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Topics:
spin [16.1K]

I need you to make me an invented poem written please not in image

3 0
2 years ago
If an object falls and ends with a velocity of 58.8 m/s, how long was the<br><br> object falling?
tensa zangetsu [6.8K]

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m

The time to fall through the height is calculated as;

h =ut+  \frac{1}{2} gt^2\\\\h = 0 +  \frac{1}{2} gt^2\\\\h =  \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s

Therefore, the time taken for the object to fall is 6 s.

6 0
3 years ago
The light from many stars can be seen from earth. but there is a time delay between the time the light is emitted from the star
mrs_skeptik [129]
Stars are located at a distance which are measured in terms of light years. Light year is an Astronomical unit used to measure distance between distant Celestial bodies. 
1 light year = 9460730472580<span>800 metres 
But no star is located at a distance of 1 light year. Some stars are located at millions of light years and light travels ~ 3 x 10</span>⁸ m/s. Thus light takes time to reach our atmosphere. 
4 0
4 years ago
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