C.
hope that helped you!!!
Answer:
Using
Period ( P) is given as
P~√(L/g).
a) since mass has no effect on the period of a pendulum. So, the period will remain 1.8seconds
b) using the formula above ,period varies with the square root of the length. Thus , when the length doubles, the period is multiplied by √2. So, the period is 1.8s*√2 = 2.54s
c) in this case, the period is multiplied by √(1/2).
1.8√(1/2)=1.27s.
d) amplitude of the pendulum doesn't affect the period (unless itsvery high, so, the period is still 1.8s
Answer:
ωf = 4.53 rad/s
Explanation:
By conservation of the angular momentum:
Ib*ωb = (Ib + Ic)*ωf
Where
Ib is the inertia of the ball
ωb is the initial angular velocity of the ball
Ic is the inertia of the catcher
ωf is the final angular velocity of the system
We need to calculate first Ib, Ic, ωb:
ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s
Now, ωf will be:
the higher concentration of molecules, the faster a reaction can occur
Answer:
11.86°
Explanation:
Projectile motion is a form of motion where an object moves in parabolic path (trajectory). Projectile motion only occurs when there is one force applied at the beginning on the trajectory, after which the only interference is from gravity.
The range of an object experiencing projectile motion is given by:
R = u²sin(2θ) / g
where u is the initial velocity, θ is the angle with horizontal and g is the acceleration due to gravity
Given that R = 6.8 m, g = 10 m/s², u = 12 m/s.
R = u²sin(2θ) / g
substituting:
6.8 = 13²sin(2θ) / 10
13²sin(2θ) = 68
sin(2θ) = 0.4024
2θ = sin⁻¹(0.4024)
2θ = 23.73
θ = 11.86°