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Alex787 [66]
4 years ago
13

A 267.5 N unbalanced force applied to push a stuffed chair across the room, causing an acceleration of 4.2 m s2 . What is the ma

ss of the chair?
Physics
2 answers:
romanna [79]4 years ago
7 0

it is B. 63.69kg !!!

Butoxors [25]4 years ago
6 0

Hi,

Data:

                          Force= F=                     267.5 N

                          Acceleration=a=           4.2 m s2 .

                          Mass of the chair= m=    ?

As we know that, according to second law of motion.

                                                  F= ma

Putting the values from the data:

                                         267.5          = m (4.2 )

                                          267.5/4.2   = m

                                          63.69         = m

                                          Mass=   63.7 kg

So, the mass of the chair will be 63.7 kg.

Hope it helps:)

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A certain thin lens is made of glass with refraction index ????lens=1.500. In air, where the index of refraction is 1.000, the l
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Answer:

The focal length of the lens in ethyl alcohol is 41.07 cm.

Explanation:

Given that,

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\dfrac{1}{f}=(n_{g}-n_{a})(\dfrac{1}{R_{1}}-\dfrac{1}{R_{2}})

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\dfrac{1}{f'}=(n_{g}-n_{ethyl})(\dfrac{1}{R_{1}}-\dfrac{1}{R_{2}})

Divided equation (II) by (I)

\dfrac{f'}{f}=\dfrac{n_{g}-n_{a}}{n_{g}-n_{ethyl}}

Where, n_{g} = refractive index of glass

n_{a} = refractive index of air

n_{ethyl} = refractive index of ethyl

Put the value into the formula

\dfrac{f'}{11.5}=\dfrac{1.500-1.000}{1.500-1.360}

\dfrac{f'}{11.5}=\dfrac{25}{7}

f'=\dfrac{25}{7}\times11.5

f'=41.07\ cm

Hence, The focal length of the lens in ethyl alcohol is 41.07 cm.

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