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3 years ago

On this, I need help on question 6

Physics

1 answer:

Nezavi [6.7K]3 years ago

8 0

5). D
The bolt of lightning is a stream of electrons flowing from
a negative to a positive part of a cloud, or either up or down
between a charged cloud and the ground.

6). D

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Assume patmos=1.00atm. what is the gas pressure pgas? express your answer in pascals to three significant figures.

hodyreva [135]

<span>Answer: Well, let's start by finding the pressure due to the "extra" height of the mercury. p = 1.36e4 kg/mÂł Â· (0.105m - 0.05m) Â· 9.8m/sÂ˛ = 7330 N/mÂ˛ = 7330 Pa The pressure at B is clearly p_b = p_atmos = p_gas + 7330 Pa The pressure at A is p_a = p_gas = p_atmos - 7330 Pa c) 1 atm = 101 325 Pa Then p_gas = 101325 Pa - 7330 Pa = 93 995 Pa</span>

8 0

3 years ago

Read 2 more answers

A smooth circular hoop with a radius of 0.400 m is placed flat on the floor. A 0.325-kg particle slides around the inside edge o

aleksandrvk [35]

Answer:

a) W = - 6.825 J, b) θ = 1.72 revolution

Explanation:

a) In this exercise the work of the friction force is negative and is equal to the variation of the kinetic energy of the particle

W = ΔK

W = K_f - K₀

W = ½ m v_f² - ½ m v₀²

W = ½ 0.325 (5.5² - 8.5²)

W = - 6.825 J

b) find us the coefficient of friction

Let's use Newton's second law

fr = μ N

y-axis (vertical) N-W = 0

fr = μ W

work is defined by

W = F d

the distance traveled in a revolution is

d₀ = 2π r

W = μ mg d₀ = -6.825

μ = $\frac{ -6.825}{d_o \ mg}$

The total work as the object stops the final velocity is zero v_f = 0

W = 0 - ½ m v₀²

W = - ½ 0.325 8.5²

W = - 11.74 J

μ mg d = -11.74

we subtitle the friction coefficient value

( $\frac{-6.8525 }{d_o mg}$ ) m g d = -11.74

6.825 $\frac{d}{d_o}$ = 11.74

d = 11.74/6.825 d₀

d = 1.7201 2π 0.400

d = 4.32 m

this is the total distance traveled, the distance and the angle are related

θ = d / r

θ = 4.32 / 0.40

θ = 10.808 rad

we reduce to revolutions

θ = 10.808 rad (1rev / 2π rad)

θ = 1.72 revolution

3 0

3 years ago

If two cars with the same mass( cars a and b) are moving but one (car b) is moving at twice the speed of car a ?

maria [59]

ANSWER:

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6 0

3 years ago

The time constant of a simple RL circuit is defined as _______. We say that R is the resistance of the circuit and L is the indu

Gennadij [26K]

Answer:

The correct answer will be " $\tau =\frac{L}{R}$ ".

Explanation:

The time it would take again for current or electricity flows throughout the circuit including its LR modules can be connected its full steady-state condition is equal to approximately 5 $\tau$ as well as five-time constants.

It would be calculated in seconds by:

⇒ $\tau=\frac{L}{R}$

, where

R seems to be the resistor function in ohms.
L seems to be the inductor function in Henries.

5 0

3 years ago

Liquid sodium can be used as a heat transfer fluid. Its vapor pressure is 40.0 torr at 633°C and 400.0 torr at 823°C. Calculate

kaheart [24]

Answer:

H vaporization = 100.0788 kJ/mol

Explanation:

Use clausius clapyron's adaptation for the calculation of Hvap as:

$ln\frac {P_2}{P_1}=\frac {H_{vap}}{R}(\frac {1}{T_1}-\frac {1}{T_2})$

Where,

P₂ and P₁ are the pressure at Temperature T₂ and T₁ respectively.

R is the gas constant.

T₂ = 823°C

T₁ = 633°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So, the temperature,

T₂ = (823 + 273.15) K = 1096.15 K

T₁ = (633 + 273.15) K = 906.15 K

P₂ = 400.0 torr , P₁ = 40.0 torr

R = 8.314 J/K.mol

Applying in the formula to calculate heat of vaporization as:

$ln \frac {400}{40}=\frac {H_{vap}}{R} (\frac {1}{906.15}-\frac {1}{1096.15})$

Solving for heat of vaporization, we get:

H vaporization = 100078.823 J/mol

Also, 1 J = 10⁻³ kJ

So,

<u>H vaporization = 100.0788 kJ/mol</u>

4 0

3 years ago