Answer:
(-∞,0)∪(0,∞)
Step-by-step explanation:
So we know that the domain is whatever X can be. We can do that by graphing the function. When we graph the function, you see that there is always an X value except at 1 point. That one point happens to be when x=0, and when x=0, the function also happens to be undefined (no number can be divided by 0). That is why the graph looks so weird. So, the answer would be
(-infinty,0) U (0, infinity)
24 + 0.44x = 19 + 1.69x
Subtract 19 from both sides
5 + 0.44x = 1.69x
Subtract 0.44x from both sides
5 = 1.25x
Divide by 1.25 on both sides
4 = x
To find perimeter you multiply.
164.042*82.021=13454.888888882 (8 repeating)
Answer:
history test
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
He did better relative to the class in the test in which he had a higher Z score.
So:
History
Raul received a score of 75 on a history test for which the class mean was 70 with a standard deviation of 7. So we have 
So:



Biology
He received a score of 73 on a biology test for which the class mean was 70 with standard deviation 7. So we have 
So:



He had a higher Z score in the history test, so this is the test in which he did better relative to the rest of the class.
Hi there!
In order to answer your question, you'll need to use the cross product method:

<u>(100 × 270)</u> ÷ 1,800 = X
<u>27,000 ÷ 1,800</u> = X
15 = X
= 15%
Your answer is: Isaac put 15% of his earnings into his savings.
There you go! I really hope this helped, if there's anything just let me know! :)