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vredina [299]
3 years ago
15

how could you estimate the volume of the box if you didn't know anything except the volume of the cylinder inside it?

Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

Since the box contains a cylinder, the height of the box must be gt; = cylinder height

And the area at the bottom of the box is definitely larger than the area at the bottom of the cylinder.

The area at the bottom of the cylinder is PI r squared,

If the bottom of the box is a square, then the area of the bottom is 4r^2, whereas the bottom tends to be polygon, which is equivalent to cutting the circle into equal parts by circle cutting.

So the area at the bottom of the box is \lim_{ Number of polygon edges\to \infty} \pi r^{2},

It follows that the volume of the box is greater than the volume of the cylinder

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The perimeter of the rectangle below is:
blondinia [14]

Answer:

18x + 28 is the perimeter

Step-by-step explanation:

As perimeter is the som of all side

So    P = 6x+8 + 3x+6 + 6x+5 + 2x+2 + 3 + x+4

          = 6x+3x+6x+2x+x + 8+6+5+2+3+4

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5 0
2 years ago
Is w^2-9w+81 a trinomial square
Yuri [45]
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
( \sqrt{a}x+ \sqrt{c})^{2} or ( \sqrt{a}x- \sqrt{c})^{2}
so
if w^2-9w+81 is perfect square, factored form is either
( \sqrt{1}x+ \sqrt{81})^{2} or ( \sqrt{1}x- \sqrt{81})^{2}  aka ( x+9)^{2} or  ( x-9)^{2}
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not






8 0
3 years ago
A intercept of 2 and slope of 1/6
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A kintted pot holder is shaped like a circle. It's radius is 4.5 in. What is the area?
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Step-by-step explanation:

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