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Semenov [28]
3 years ago
8

What is the oxidation state of a lone element?

Chemistry
2 answers:
ki77a [65]3 years ago
7 0

Answer:

i think the answer is b or c

11Alexandr11 [23.1K]3 years ago
3 0
I think it is C or A
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Gaseous BF3 and BCl3 are mixed in equal molar amounts. All B-F bonds have about the same bond enthalpy, as do all B-Cl bonds. Co
lord [1]

Solution :

$BF_3 (g) + BCl_3 (g) \rightarrow BF_2 Cl + BCl_F(g)$

<u>Explanation 1 </u>:

Spontaneity of the reaction is based on two factors :

-- the tendency to acquire a state of minimum energy

-- the energy of a system to acquire a maximum randomness.

Now, since there isn't much difference in the bond enthalpies of B-F and B-Cl. So, we can say the major driving factor is tendency to acquire a state of maximum randomness.

<u>Explanation 2 </u>:

A system containing the \text{"chemically mixed"} B halides has a \text{greater entropy} than a system of $BCl_3$ and BF_3.

It has the same number of \text{gas phase molecules}, but more distinguishable kinds of \text{molecules}, hence, more microstates and higher entropy.

8 0
3 years ago
A student performs the reduction of 4-nitrobenzaldehyde (151.12 g/mol) with sodium borohydride (37.83 g/mol) in the presence of
Leviafan [203]

Answer:

65.4%

Explanation:

The redox reaction is a 1:1:1 reaction because the reagents suffer a double displacement reaction, and the substance that is substituted have the same charge (H+ and Br-), thus, we first need to know which of the reagents is the limiting.

Let's test the 4-nitrobenzaldehyde as the limiting. The mass needed for sodium borohydride (m) is the mass given of 4-nitrobenzaldehyde multiplied by the stoichiometric mass of sodium borohydride divided by the stoichiometric mass of 4-nitrobenzaldehyde. The stoichiometric mass is the number of moles in the stoichiometric representation (1:1:1) multiplied by the molar mass, so:

m = (4.13 * 37.83*1)/(151.12*1)

m = 1.034 g

So, the mass needed of the other reagent is larger than the mass that was given, so, it will be the limiting, and the stoichiometric calculus must be done with it.

The mass of the product that was expected is then:

m = (0.700*153.14*1)/(37.83*1)

m = 2.83 g

The percent yield is the mass that was formed divided by the expected mass, and then multiplied by 100%:

%yield = (1.85/2.83)*100%

%yield = 65.4%

8 0
3 years ago
What will increase the salt concentration in seawater?
MA_775_DIABLO [31]

Answer:

Evaporation process

Explanation:

The evaporation process is responsible for the increase in the concentration of salt in the oceans or seawater.

Within the ocean there are certain places where there occurs little or no rainfall. The temperature in this region is relatively high and dry, due to which there occurs the process of evaporation. Because of the absence of rainfall, the rate of evaporation is higher in this region compared to the rate of precipitation. So when this process takes place, it eliminates the water quantity present in it, resulting in the formation of salts.

The salinity of the ocean increases because of the high rate of evaporation of the ocean water as well as forming of the sea ice.

8 0
4 years ago
What is the name of two areas where rivers leave rich, fertile soil?
Tom [10]

Answer:

1] flood planes

2] deltas

5 0
3 years ago
2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)<br> how many atoms are in 3.2 moles of KCl?
Gekata [30.6K]

Answer:

If u use math why It will give u the answer like 3x3=9

Explanation:

4 0
3 years ago
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