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2 years ago

14. Energy (heat) is always transferred from _ energy to _ energy

Chemistry

1 answer:

Blababa [14]2 years ago

5 0

Answer:i pretty sure it is high to low kinetic

Explanation: because heat or energy travels from hot heat to low heat which heat is the same as kinetic

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The head loss in a turbulent flow in a pipe varies Approximant as square of velocity • Direct as the velocity • Invers as square

Eddi Din [679]

Answer:

Head loss in turbulent flow is varying as square of velocity.

Explanation:

As we know that head loss in turbulent flow given as

$h_F=\dfrac{FLV^2}{2gD}$

Where

F is the friction factor.

L is the length of pipe

V is the flow velocity

D is the diameter of pipe.

So from above equation we can say that

$h_F\alpha V^2$

It means that head loss in turbulent flow is varying as square of velocity.

We know that loss in flow are of two types

1.Major loss :Due to surface property of pipe

2.Minor loss :Due to change in momentum of fluid.

5 0

2 years ago

Read 2 more answers

A clear, pure liquid sample is brought into the lab and exposed to an electrical current. Different gases are

mel-nik [20]

I think it’s a d but I’m not sure

4 0

2 years ago

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Calculate the mole fraction of the ionic species kcl in the solution.

sp2606 [1]

The question is incomplete, here is the complete question:

Calculate the mole fraction of the ionic species KCl in the solution A solution was prepared by dissolving 43.0 g of KCl in 225 g of water.

Answer: The mole fraction of KCl in the solution is 0.044

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For water:

Given mass of water = 225 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{225g}{18g/mol}=12.5mol$

For KCl:

Given mass of KCl = 43 g

Molar mass of KCl = 74.55 g/mol

Putting values in equation 1, we get:

$\text{Moles of KCl}=\frac{43g}{74.55g/mol}=0.577mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For KCl:

Moles of KCl = 0.577 moles

Total moles = [0.577 + 12.5] = 13.077 moles

Putting values in above equation, we get:

$\chi_{(KCl)}=\frac{0.577}{13.077}=0.044$

Hence, the mole fraction of KCl in the solution is 0.044

8 0

2 years ago

Frozen ice caps in the Arctic Ocean are composed of?

rjkz [21]

Answer

D a mixture of salt and fresh water

4 0

2 years ago

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Balance the following redox equation, using half-reactions. Assume that the reaction occurs in an aqueous solution.

anastassius [24]

First determine the formal oxidation numbers:
N changes from +2 to +5 going from NO to (NO3)- O remains -2 the whole time Cr changes from +6 to +3
Now write the half reactions, balance the oxygens with the required number of waters and then balance the hydrogens with the required number of protons:
Oxidation half reaction:
NO(aq) + 2 H2O(l) ---> (NO3)-(aq) + 4 H+(aq) + 3 e-
Reduction half reaction:
(Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l)
Now balance the number of electrons on both sides and add them together:
2 NO(aq) + 4 H2O(l) ---> 2 (NO3)-(aq) + 8 H+(aq) + 6 e- (Cr2O7)2-(aq) + 14 H+(aq) + 6 e- ---> 2 Cr3+(aq) + 7 H2O(l) --------------------------------------... 2 NO(aq) + (Cr2O7)2-(aq) + 6 H+(aq) ---> 2 (NO3)-(aq) + 2 Cr3+(aq) + 3 H2O(l)
Notice that the charge is the same in both sides, which is an indication that the redox equation has been balanced correctly:
-2 + 6 = -2 + 2(+3) +4 = +4

5 0

2 years ago

14. Energy (heat) is always transferred from ___ energy to ___ energy

14. Energy (heat) is always transferred from _ energy to _ energy