Help pls pls Polk brain if correct

Need help with 13 14 and 15

ad-work [718]

Answer:

njbvi3brfjkncdoewkmdrfrj

Step-by-step explanation:

gagagagagaggag

6 0

2 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

or

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

or

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

2 years ago

A solution of salt and water is 20% salt. If 25% of the water is removed, what is the percentage of salt in the new solution?

Ratling [72]

So lets say that this salt and water solution consists of 100 liters.

Then that means 20 liters is salt, and 80 liters out of the 100 is water.

Now, we remove 25% of the water. 25% of 80 liters is 20 liters. So, we are left with 80-20, or 60 liters.

Now in all we have 20 liters of salt, and 60 liters of water.

The percentage of salt in the new mixture will be 20/(20+60) = 20/80 = 25%.

Your answer is 25%

4 0

2 years ago

A sand wedge normally costs 65.00. It is on sale for 20% off the regular price. what is the discount

r-ruslan [8.4K]

Answer:$52.00

Step-by-step explanation:

5 0

2 years ago

Tell whether each scale reduces enlarges or preserves the size of an actual object

mr_godi [17]

Given:

1 m : 25 cm

8 in : 1 ft

12 in : 1 ft

First, we convert each variable given on the right:

1 m : 0.25 m (this means that 1 meter is made to represent 25 cm)

8 in : 12 feet (this means that 8 in is made to represent 1 feet)

12 in : 12 in (this means that 12 in is made to represent 1 feet)

<span>After converting the variables, we can now know if the ratios are enlargement, reduction or preservation. Therefore:

1 m : 25 cm = Enlarge</span>

<span>8 in : 12 feet = Reduce
12 in = 1 ft = Preserve</span>

4 0

2 years ago

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