To calculate the distance between 2 points we will use the following equation:
![D=\sqrt[]{(x_2-x_1)^2-(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2-%28y_2-y_1%29%5E2%7D)
For this exercise we have the following data:

We plug the values into the distance equation and solve for the unknown Y
Answer:
- 7
- see below
- 5
- the rule is not one-to-one
Step-by-step explanation:
Applying the squaring rule to each of the elements of the domain, we get ...

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1. There are 7 different numbers in the Domain list.
2. See above
3. There are 5 different numbers in the Range list.
4. The rule "square me" is not "one-to-one" Two different values in the domain can result in the same value in the range. -3 and 3 both result in 9. -1/2 and 0.5 both result in 1/4.
Sum of a number, n and 21...." the sum " means add
n + 21
if n = 8
8 + 21 = 29....the sum is 29
First, you have to simplify the equation:
y+3 = 3(x+5)
y+3=3x+15
So you multiply what’s inside the brackets (x+5) by the factor (3). So 3•x=3x, 3•5=15.
Then you rearrange the equation as necessary to convert it into standard form, which is Ax + By = C
X=4, first you distribute the 2 to both 4x and -11 which leaves you with 8x-22+9=19 next you add -22 with 9 which leaves you -13 the eqation now at 8x-13=19 so now you add 13 to both sides now youre left with 8x=32. Now the last step is to divide 8 on both sides. so that gives you the answer or X=4