Question

If f(x) = –2x3, g(x) = 3x – 5, and h(x) = x – 1, what is f(g(h(3)))? –129 –54 –53 –2

Answer 1

Answer:

$f(x) = - 2 {x}^{3} \\ g(x) = 3x - 5 \\ h(x) = x - 1 \\ g(h(x)) = 3(x - 1) - 5 \\ = 3x - 3 - 5 = 3x - 8 \\ f(g(h(x)) )= - 2 {(3x - 8)}^{3} \\ f(g(h(3)) )=- 2 {(3(3) - 8)}^{3} \\ = - 2 {(9 - 8)}^{3} \\ f(g(h(3)) )=- 2$