Answer:
the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403
Step-by-step explanation:
P( x > 193) = 0.15
= 1- p(x less than or equal 193)
= 1 -p( z < (x- u) /sigma)
= 1- p( z< (193 - 187)/ sigma)
= 1- p( z< 6/ sigma)
P(z< 6/sigma) = 1 - 0.15
P(z < 6/sigma)= 0.85
6/sigma =1.036
Sigma= 6/1.036
Sigma= 5.79
P( x> 185) = 1- p( x< 185)
= 1- p (z < (185- 187)/5.79)
= 1- p( z< -0.345)
= 1- 0.365
= 0.635
P (x> 185) = 0.635 × 0.635
=0.403
Hello!!
Isolate the variable by dividing each side by factors that don't contain the variable.
Your answer is 12.5.
Hope that you pass your test!!
Answer:
1/2
Step-by-step explanation:
9/16 is equal to 0.5625
. The closest number to this is 0.5 which is the same as 1/2
F(x)=1-x² and g(x)=√(11-4x)
(g+f)(2)=>
1-(2)²+√(11-4(2))
=√3-3
(f/g)(-1)
(1-(-1)²)/(√(11-4(-1))
=0
(g-f)(-1)
√(11-4*-1)-(1-(-1)²
=√15
(g×f)(2)
1-(2)²×√(11-4(2))
-3√3