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GalinKa [24]
2 years ago
8

Find the area of this shape. please help

Mathematics
1 answer:
mamaluj [8]2 years ago
4 0

Answer:

Step-by-step explanation:

Divide and Conquer:

Make shapes you know how to find the area of

(4x5.75)+8+4=35 cm^2

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Find the midpoint M of the line segment joining the points P= (-7,-8) and Q = (3,2)
Fed [463]

Answer:

(-2, -3)

Step-by-step explanation:

To solve this problem, we use the midpoint formula.

M = \frac{x1 + x2}{2} , \frac{y1+ y2}{2}

Plug your coordinates in:

M = \frac{-7 + 3}{2} , \frac{-8 + 2}{2}

Simplify:

M = \frac{-4}{2} , \frac{-6}{2}

M = (-2,-3)

3 0
3 years ago
TRUE OR FALSE in JkL and PQR if J equals P & K. Equals Q
slava [35]
The answer is false.
There is no "AAA (angle-angle-angle)" postulate. Two triangles can have all of their angles congruent, but that does not mean all of the sides are equal. Therefore, the triangle may not be congruent.
4 0
3 years ago
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4m - 8 = 10 - 2m<br> solve for m
Goryan [66]

Answer:

Step-by-step explanation:

4m - 8 = 10 - 2m

6m - 8 = 10

6m = 18

m = 3

4 0
3 years ago
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Instructions: Given the vertex, fill in the vertex form of the quadratic function..
miskamm [114]

Answer:

\implies y=(x-2)^2-6

Step-by-step explanation:

<u>Vertex form of a quadratic equation</u>:

y=a(x-h)^2+k

where:

  • (h, k) is the vertex
  • a is some constant

<u>Given vertex</u>:  (2, -6)

⇒ h = 2 and k = -6

Substitute the values of h and k into the formula:

\implies y=a(x-2)^2+(-6)

\implies y=a(x-2)^2-6

As we have not been given a value for the constant a, assume this is 1.

Therefore, the <u>vertex form</u> of the <u>quadratic function</u> with vertex (2, -6) is:

y=(x-2)^2-6

Learn more about vertex form here:

brainly.com/question/27796555

brainly.com/question/27909020

5 0
2 years ago
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A swimmer is racing to the other side of the
kiruha [24]
Either B or C. They look exactly the same but I can’t tell because the photo is blurry

y intercept is 75 and x intercept is 75/2.5=30
4 0
3 years ago
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