3t=4s+5 (s=side of square, t= side of triangle)
s=t-3, t=s+3, using this value for t in the first equation gives us:
3(s+3)=4s+5
3s+9=4s+5
-s=-4
s=4
so the side length of the square is 4cm and the area of a square is just s^2
A=16cm^2
Answer:
Guess what?
Step-by-step explanation:
None of them have the same value
Answer:
There would be no property because it doesn't form any conic sections.
Hope this helped :)
P.S. Are there answer choices?
<h3>
Answer: 21</h3>
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Work Shown:
The diagram shows that JK = 12 and GF = 2.5*(JK) = 2.5*12 = 30
The midsegment HL will be the average of the two lengths it is parallel to.
We'll add up the values and then cut the result in half
HL = (JK+GF)/2
HL = (12+30)/2
HL = 42/2
HL = 21
