The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.
Step-by-step explanation:
Given,
The distance traveled by plane = 1463 miles
The trip with the wind took 11 hours.
The trip took 19 hours against the wind.
Let,
s be the speed of plane and w be the speed of wind.
Therefore;
Speed with the wind = s+w
Speed into the wind = s-w
We know that;
Distance = Speed * Time
Therefore;
Equation for trip taken with wind.
1463 = 11(s+w)
Dividing both sides by 11
Equation for trip taken into the wind
1463 = 19(s-w)
Dividing both sides by 19
Adding Eqn 1 and 2
Dividing both sides by 2
Putting s=105 in Eqn 1
The speed of plane is 105 miles per hour and speed of wind is 28 miles per hour.
Answer:
1.6
Step-by-step explanation:
Answer:
I'm pretty sure it is 2ab×(a+3b)
Answer:
Step-by-step explanation:
The formula for determining the distance between two points on a straight line is expressed as
Distance = √(x2 - x1)² + (y2 - y1)²
Where
x2 represents final value of x on the horizontal axis
x1 represents initial value of x on the horizontal axis.
y2 represents final value of y on the vertical axis.
y1 represents initial value of y on the vertical axis.
From the points given,
x2 = 0
x1 = 9
y2 = - 33
y1 = 7
Therefore,
Distance = √(0 - 9)² + (- 33 - 7)²
Distance = √(- 9² + (- 40)² = √(81 + 1600) = √1681
Distance = 41
The formula determining the midpoint of a line is expressed as
[(x1 + x2)/2 , (y1 + y2)/2]
[(9 + 0) , (7 - 33)]
= (9, - 26]
Answer:
y = -21x
Step-by-step explanation:
If you divide the y by -21 you should end up with x, hope this helps.
