For this question, we determine first the x and y components of the distances.
3 blocks north:
x - component = +3 ; y-component = 0
4 blocks northeast:
x - component = (cos 45°)(4 blocks) = 2.83 blocks
y - component = (cos 45°)(4 blocks) = 2.83 blocks
5 blocks west:
x-component = -5 ; y-component = 0
Then, we add up all the x-components and all the y-components
x-component (sum) = 0.83
y-component (sum) = 2.83
Then, we determine the magnitude of the block by the equation below.
m = √(x² + y²) = √(0.83² + 2.83²) ≈ 2.95 blocks
Thus, the displacement from the original position is approximately equal to 2.95 blocks.
Answer:
W = 2.200 Joules
Explanation:
Datos (data):
- Fuerza [force] (F) = 110 N
- Metros [meters] (m) = 20 m
- Trabajo [work] (W) = ?
Usar la fórmula (use formula):
Reemplazar (replace):
Resolver la multiplicación, recuerda que 1 N * 1 m = 1 J (resolve the multiplication, remember that 1 N * 1 m = 1 J:
Greetings.
Answer:
A sailboat moves north for a distance of 10.00 km when blown by a wind from the eaxct southeast with a force of 5.00 X 10^4 N. How much work was done by the wind?
Explanation: