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riadik2000 [5.3K]
2 years ago
8

Describe and explain the motion of a small ball floating on a pond when waves travel across the pond

Physics
1 answer:
laila [671]2 years ago
4 0
I think the answer is periodic motion.
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How do the current and coltage readings compare to before the wires were switched. Explain how to interpret them physically?
Blababa [14]
  • The potential difference between two locations in an electric circuit is measured using a voltmeter.
  • If the electricity passes through the voltmeter it shows deflection.

<h3>What is the purpose of a voltmeter?</h3>
  • A voltage meter, usually referred to as a voltmeter, is a device that measures the voltage, or potential difference, between two points in an electrical or electronic circuit.
  • volts is the unit of voltmeter(volts, millivolts, kilovolts)

<h3>What is the explanation for the link between current and voltage?</h3>
  • Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.

<h3>What is ohm's law in circuit?</h3>
  • V = IR, where V is voltage, I is current, and R is resistance, is known as Ohm's Law.
  • If you know the voltage of the battery in the circuit and how much resistance is in the circuit, you may use Ohm's Law to identify properties of a circuit, such as how much current is flowing through it.

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7 0
1 year ago
PLEASEEE HELPPPP
solniwko [45]

Answer:

Explanation:

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5 0
3 years ago
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What is the law of conservation of energy?
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The law of conservation of energy<span>, a fundamental concept of physics, states that the total amount of </span>energy<span> remains constant in an isolated system. It implies that </span>energy<span> can neither be created nor destroyed, but can be change from one form to another.</span>
6 0
2 years ago
The melting point of pure water is _____.<br><br> 32°C<br><br> 100°C<br><br> 0°C<br><br> 212°C
BabaBlast [244]

Answer:

0°C and 32°F

Explanation:

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3 0
2 years ago
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Two manned satellites approach one another at a relative velocity of v=0.190 m/s, intending to dock. The first has a mass of m1=
drek231 [11]

Answer:

Their final relative velocity is 0.190 m/s

Explanation:

The relative velocity of the satellites, v = 0.190 m/s

The mass of the first satellite, m₁ = 4.00 × 10³ kg

The mass of the second satellite, m₂ = 7.50 × 10³ kg

Given that the satellites have elastic collision, we have;

v_2 = \dfrac{2 \cdot m_1}{m_1 + m_2} \cdot u_1 - \dfrac{m_1 - m_2}{m_1 + m_2} \cdot u_2

v_2 = \dfrac{ m_1 - m_2}{m_1 + m_2} \cdot u_1 + \dfrac{2 \cdot m_2}{m_1 + m_2} \cdot u_2

Given that the initial velocities are equal in magnitude, we have;

u₁ = u₂ = v/2

u₁ = u₂ = 0.190 m/s/2 = 0.095 m/s

v₁ and v₂ = The final velocities of the satellites

We get;

v_1 = \dfrac{2 \times 4.0 \times 10^3}{4.0 \times 10^3 + 7.50 \times 10^3} \times 0.095 - \dfrac{4.0 \times 10^3- 7.50\times 10^3}{4.0 \times 10^3+ 7.50\times 10^3} \times 0.095 = 0.095

v_2 = \dfrac{ 4.0 \times 10^3 - 7.50\times 10^3}{4.0 \times 10^3 + 7.50 \times 10^3} \times 0.095 + \dfrac{2 \times 7.50\times 10^3}{4.0 \times 10^3+ 7.50\times 10^3} \times 0.095 = 0.095

The final relative velocity of the satellite, v_f = v₁ + v₂

∴ v_f = 0.095 + 0.095 = 0.190

The final relative velocity of the satellite, v_f = 0.190 m/s

4 0
2 years ago
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