Describe and explain the motion of a small ball floating on a pond when waves travel across the pond

How do the current and coltage readings compare to before the wires were switched. Explain how to interpret them physically?

Blababa [14]

The potential difference between two locations in an electric circuit is measured using a voltmeter.
If the electricity passes through the voltmeter it shows deflection.

<h3>What is the purpose of a voltmeter?</h3>

A voltage meter, usually referred to as a voltmeter, is a device that measures the voltage, or potential difference, between two points in an electrical or electronic circuit.
volts is the unit of voltmeter(volts, millivolts, kilovolts)

<h3>What is the explanation for the link between current and voltage?</h3>

Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.

<h3>What is ohm's law in circuit?</h3>

V = IR, where V is voltage, I is current, and R is resistance, is known as Ohm's Law.
If you know the voltage of the battery in the circuit and how much resistance is in the circuit, you may use Ohm's Law to identify properties of a circuit, such as how much current is flowing through it.

To learn more about current and voltage visit:

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7 0

1 year ago

PLEASEEE HELPPPP

solniwko [45]

Answer:

Explanation:

average speed more than 25.0m/s.

5 0

3 years ago

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What is the law of conservation of energy?

charle [14.2K]

The law of conservation of energy<span>, a fundamental concept of physics, states that the total amount of </span>energy<span> remains constant in an isolated system. It implies that </span>energy<span> can neither be created nor destroyed, but can be change from one form to another.</span>

6 0

2 years ago

The melting point of pure water is _____.<br><br> 32°C<br><br> 100°C<br><br> 0°C<br><br> 212°C

BabaBlast [244]

Answer:

0°C and 32°F

Explanation:

ihavetotypemoresouhyeahig

3 0

2 years ago

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Two manned satellites approach one another at a relative velocity of v=0.190 m/s, intending to dock. The first has a mass of m1=

drek231 [11]

Answer:

Their final relative velocity is 0.190 m/s

Explanation:

The relative velocity of the satellites, v = 0.190 m/s

The mass of the first satellite, m₁ = 4.00 × 10³ kg

The mass of the second satellite, m₂ = 7.50 × 10³ kg

Given that the satellites have elastic collision, we have;

$v_2 = \dfrac{2 \cdot m_1}{m_1 + m_2} \cdot u_1 - \dfrac{m_1 - m_2}{m_1 + m_2} \cdot u_2$

$v_2 = \dfrac{ m_1 - m_2}{m_1 + m_2} \cdot u_1 + \dfrac{2 \cdot m_2}{m_1 + m_2} \cdot u_2$

Given that the initial velocities are equal in magnitude, we have;

u₁ = u₂ = v/2

u₁ = u₂ = 0.190 m/s/2 = 0.095 m/s

v₁ and v₂ = The final velocities of the satellites

We get;

$v_1 = \dfrac{2 \times 4.0 \times 10^3}{4.0 \times 10^3 + 7.50 \times 10^3} \times 0.095 - \dfrac{4.0 \times 10^3- 7.50\times 10^3}{4.0 \times 10^3+ 7.50\times 10^3} \times 0.095 = 0.095$

$v_2 = \dfrac{ 4.0 \times 10^3 - 7.50\times 10^3}{4.0 \times 10^3 + 7.50 \times 10^3} \times 0.095 + \dfrac{2 \times 7.50\times 10^3}{4.0 \times 10^3+ 7.50\times 10^3} \times 0.095 = 0.095$

The final relative velocity of the satellite, $v_f$ = v₁ + v₂

∴ $v_f$ = 0.095 + 0.095 = 0.190

The final relative velocity of the satellite, $v_f$ = 0.190 m/s

4 0

2 years ago