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3 years ago

Forces cause objects to

Physics

2 answers:

inessss [21]3 years ago

4 0

Answer:

ccccccccccc

Explanation:

is the answer

Dafna11 [192]3 years ago

3 0

Answer:

c accelerate

Explanation:

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A shopping cart is pushed and released,

Wewaii [24]

The magnitude of the friction on the cart is 28,56 N

To measure the deceleration of a car, without the value of the time of the movement, the <u>Torricelli equation</u> is used, which consists of:

${v_{f}}^{2}={v_{o}}^{2}+2a\Delta s$

Where is final velocity, is initial velocity, is acceleration, and is displacement.

Now, substitute the values in the formula:

$0^{2} = (3.5)^{2} + 2a6$

$0 = 12.25 + 12a$

$a = -\frac{12.25}{12}$

$a = -1.02$

Finally, the value of the acceleration found is multiplied by the mass of the object, thus measuring the friction force:

$F = 28\times-1.02$

$F = -28.56 N$

Learn more about friction force at: brainly.com/question/13707283

5 0

3 years ago

a ball is thrown straight up into the air with a speed of 13 m/s. if the ball has a mass of 0.25 kg, how high does the ball go?

evablogger [386]

<h2>Hello!</h2>

The answer is: 8.62m

There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.

<h2>First moment:</h2>

Before the ball is thrown, where the potential energy is 0.

<h2>Second moment: </h2>

After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.

Therefore,

$E=PE+KE$

Where:

$PE=m.g.h$

$KE=\frac{1*m*v^{2}}{2}$

<em>E</em> is the total energy

<em>PE</em> is the potential energy

<em>KE</em> is the kinetic energy

<em>m</em> is the mass of the object

<em>g</em> is the gravitational acceleration

<em>h </em>is the reached height of the object

<em>v</em> is the velocity of the object

Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:

$KE_{1}+PE_{1}=KE_{2}+PE_{2}$

Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.

$\frac{1*m*v^{2}}{2}+m.g.(0)=\frac{1*m*0^{2}}{2}+m.g.h\\\frac{1*m*v_{1} ^{2}}{2}=m*g*h_{2}$