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Andrej [43]
3 years ago
14

What are the correct answers?​

Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

BAKING TINS

Step-by-step explanation:

Use the Pythagorean Theorem to solve = a^{2} +b^{2} = c^{2}.

2) 8² + 6² = c²

64 + 36 = 100

\sqrt{100}

x = 10 = I

3) 10² - 9² = a²

100 - 81 = 19

\sqrt{19}

x = 4.4 = G

4) 8.8² + 3.2² = c²

77.44 + 10.24 = 87.9

\sqrt{87.9}

x = 9.4 = B

5) 27² - 24² = a²

729 - 576 = 153

\sqrt{153}

x = 12.4 = S

6) 11² - 7² = a²

121 - 49 = 72

\sqrt{72} = 8.5

13² + 8.5² = c²

169 + 72.25 = 241.25

\sqrt{241.25}

x = 15.5 = T

7) 22.1² + 14.2² = c²

488.41 + 201.64 = 690.1

\sqrt{690.1}

x = 26.3 = K

8) 32² + 41² = c²

1024 + 1681 = 2705

\sqrt{2705}

x = 52 = N

Hope it helps!

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Answer:

187.9436

Step-by-step explanation:

Multiply

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3 years ago
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I need this answer plzzz!!
Dmitriy789 [7]

Answer: True, False, False, False, False

<u>Step-by-step explanation:</u>

a) 5x - 7(x - 1)

   5x - 7x + 7

         -2x + 7   ⇒  a = -2, b = 7   <em>One Solution</em>

b) 3(x - 5) - 7

   3x - 15 - 7

       3x - 22   ⇒  a = 3, b = -22   <em>One Solution</em>

c) 2 - 7x + 3 + 4x

  4x - 7x + 3 + 2  

              -3x + 5  ⇒   a = -3, b = 5   <em>One Solution</em>    

d) -3(x - 3) - 1

   -3x + 9 - 1

       -3x + 8   ⇒   a = -3, b = 8   <em>One Solution</em>

e) -5x + 2 + 2x + 4

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4 0
3 years ago
In the expression a + 2b − 12c2, a, 2b, and −12c2 are examples of _____
Vaselesa [24]
Answer:
Terms

Explanation:
Any expression is formed of terms separated by addition or subtraction.
A term can be a number, a variable or the product of multiplying a number and a variable.
Now, the given expression is:
a + 2b + 12c^2
This expression has three terms all separated by addition. These terms are:
a : which is only a variable
2b : which is the product of a number and a variable
12c^2 : which is the product of a number and a variable

Hope this helps :)
8 0
3 years ago
Use triangle ABC drawn below &amp; only the sides labeled. Find the side of length AB in terms of side a, side b &amp; angle C o
Brrunno [24]

Answer:

AB = \sqrt{a^2 + b^2-2abCos\ C}

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

Sin\ C = \frac{h}{a}

Make h the subject:

h = aSin\ C

Also, in BOC (Using Pythagoras)

a^2 = h^2 + x^2

Make x^2 the subject

x^2 = a^2 - h^2

Substitute aSin\ C for h

x^2 = a^2 - h^2 becomes

x^2 = a^2 - (aSin\ C)^2

x^2 = a^2 - a^2Sin^2\ C

Factorize

x^2 = a^2 (1 - Sin^2\ C)

In trigonometry:

Cos^2C = 1-Sin^2C

So, we have that:

x^2 = a^2 Cos^2\ C

Take square roots of both sides

x= aCos\ C

In triangle BOA, applying Pythagoras theorem, we have that:

AB^2 = h^2 + (b-x)^2

Open bracket

AB^2 = h^2 + b^2-2bx+x^2

Substitute x= aCos\ C and h = aSin\ C in AB^2 = h^2 + b^2-2bx+x^2

AB^2 = h^2 + b^2-2bx+x^2

AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2

Open Bracket

AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C

Reorder

AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C

Factorize:

AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C

In trigonometry:

Sin^2C + Cos^2 = 1

So, we have that:

AB^2 = a^2 * 1 + b^2-2abCos\ C

AB^2 = a^2 + b^2-2abCos\ C

Take square roots of both sides

AB = \sqrt{a^2 + b^2-2abCos\ C}

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3 years ago
Randy walks 1/2 mile in each 1/5 hour. How far did randy walk in 1 hour in decimal
Lerok [7]

there are 5 1/5 in an hour

 so multiply 1/2 by 5

1/2 = 0.5

0.5 *5 = 2.5 miles in 1 hour

5 0
4 years ago
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