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yulyashka [42]
2 years ago
6

Evaluate. 3⋅23+52−18÷6 25 31 40 46

Mathematics
1 answer:
scoray [572]2 years ago
6 0
Photo has the answer

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What two numbers multiply to get 45 but add to get -10?
goldenfox [79]
There are no two numbers that multiply to 45 but add to -10.
This is because the only numbers that multiply to get 45 are 1x45, 3x15, 5x8. None of them can add to -10 even if you make some of the numbers negative instead.

If this is a factoring problem, you may have to use the quadratic equation instead.
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2 years ago
How you divided numbers
german

Answer:

Step-by-step explanation:

It really depend what number, or what type of number you are multiplying, it's kind of like multiplication you're just doing it backwards. Say that you were trying to divide 20 by 5 you think in your head OK five times what equals 20 and your answer would be four because 5×4 is 20 that's the easiest way to think of it that did not help you with your question tell me in the comments and I will find a better way to explain it.

7 0
3 years ago
Evaluate the logarithmic equation:
evablogger [386]

Answer

simplified is log5 (2)

the 5 is suposed to be the subscript one.

6 0
2 years ago
Select the statement that describes this expression: 13 + fraction 1 over 2 x (6 ÷ 2 + 6)
amid [387]
I think the answer is B
3 0
3 years ago
Read 2 more answers
What are the correct answers and why? Simple and concise explanation please!!!
dezoksy [38]

Answer:

\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}

Step-by-step explanation:

(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)

f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1

-----------------------------------------

-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8

-----------------------------------

-x^2+4x-8=-x^2+4x-2^2+2^2-8=-(x^2-4x+2^2)+4-8\\\\=-(\underbrace{x^2-(2)(x)(2)+2^2}_{(a-b)^2=a^2-2ab+b^2})-4=-(x-2)^2-4=-(x+1-3)^2-4

In\ (-x+1-3)^2+2x,\ x^2\ will\ be\ positive.\\In\ (-x+1-3)^2+2(-x+1),\ x^2\ will\ be\ positive.

6 0
3 years ago
Read 2 more answers
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