Answer:
Step-by-step explanation:
C
20% discount is definitely the $ saver!
Answer:
30 degrees
Step-by-step explanation:
Since we know that all triangles equal 180 degrees, we can add the 2 given angles and subtract that from 180 to find the remaining angle.
90+60=150
180-150=30 degrees
Answer:
The second graph near the bottom with a Y-intercept of -1
Answer:
Length of B is 7.4833
Step-by-step explanation:
The vector sum of A and B vectors in 2D is

And its magnitude is:

Where




Using the properties of the sum of two angles in the sin and cosine:


Sustituying in the magnitud of the sum




Solving for B


Sustituying the value of the magnitud of A

