area of OAB = 72 = (1/2) sin (AOB) * OA * OB solve the above for sin(AOB) to find sin(AOB) = 1/2 area of ODC = 288 = (1/2) sin (DOC) * OD * OD Note that sin(DOC) = sin(AOB) = 1/2, OD = 18 + y and OC = 16 + x and substitute in the above to obtain the first equation in x and y 1152 = (18 + y)(16 + x)...
<em><u>HOPE</u></em><em><u> </u></em><em><u>SO</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>HELPS</u></em><em><u> </u></em><em><u>YOU</u></em>
FGJLPQR Are some letters with no rotational or line symmetry
First you set up the problem- 7/12=x/100. then you cross multiply 7×100=700 then divide 12 into 700 so 700÷12=58.333333333333 and so your percentage is 58.3%
Answer:
(3,-3)
Step-by-step explanation: