Answer:
So (L,W) possibilities are:
(1,4),(4,1),(2,3),(3,2)
That makes 4 possibilities.
Step-by-step explanation:
The perimeter of a rectangle is P=2L+2W where L is the length and W is the width.
We have that P=10, so 10=2L+2W.
10=2L+2W
10=2(L+W) By factoring using the distributive property.
2(5)=2(L+W) I factored 10 as 2(5).
If 2(5)=2(L+W), then 5=L+W.
Whole numbers are {0,1,2,3,4,5,6,7,8,9,10,...}. They are your counting numbers and 0.
I think they want natural numbers {1,2,3,4,...}. This is also just called the counting numbers. The reason I think they want this because if one of the dimensions is 0, we won't actually have a rectangle.
So now looking for numbers from this set that satisfy: L+W=5.
L+W=5
1+4=5
4+1=5
2+3=5
3+2=5
So (L,W) possibilities are:
(1,4),(4,1),(2,3),(3,2)
That makes 4 possibilities.
