Answer:
Speed is a "scalar" quantity
(C) is the correct answer
An object could travel at 10 m/s to some point and then return to the origin at 10 m/s for an average speed of 10 m/s, however it's displacement over that time would be zero for a net velocity of zero.
Answer:
The current in the wire is 31.96 A.
Explanation:
The current in the wire can be calculated as follows:

<u>Where</u>:
q: is the electric charge transferred through the surface
t: is the time
The charge, q, is:

<u>Where</u>:
n: is the number of electrons = 7.93x10²⁰
e: is the electron's charge = 1.6x10⁻¹⁹ C

Hence, the current in the wire is:

Therefore, the current in the wire is 31.96 A.
I hope it helps you!
Answer:
B - Divide Speed and Distance
Explanation:
Hope it helps!!
:D
1) 5 s
The vertical position of the object is given by

where
h=400 ft represents the initial height
g = 32 ft/s^2 is the acceleration of gravity
t is the time
We want to find the time t at which the object reaches the ground, so the time t at which
y(t) = 0
By substituting this into the equation, we find

2) 160 ft/s
The object is released from rest, so the initial velocity is zero
u = 0
The final vertical velocity can be found by using

where
v is the final velocity
a = 32 ft/s^2 is the acceleration of gravity
h = 400 ft is the vertical distance covered
Solving for v, we find
