The speed of the 2 kg cart after 5 seconds is ? cm/s.

Light travels through a liquid at 2.25e8 m/s. What is the index of refraction of the liquid?

Pavlova-9 [17]

Answer:

The index of refraction of the liquid is n = 1.33 equivalent to that of water

Explanation:

Solution:-

- The index of refraction of light in a medium ( n ) determines the degree of "bending" of light in that medium.

- The index of refraction is material property and proportional to density of the material.

- The denser the material the slower the light will move through associated with considerable diffraction angles.

- The lighter the material the faster the light pass through the material without being diffracted as much.

- So, in the other words index of refraction can be expressed as how fast or slow light passes through a medium.

- The reference of comparison of how fast or slow the light is the value of c = 3.0*10^8 m/s i.e speed of light in vacuum or also assumed to be the case for air.

- so we can mathematically express the index of refraction as a ratio of light speed in the material specified and speed of light.

- The light passes through a liquid with speed v = 2.25*10^8 m/s :

$n = c / v\\\\n = \frac{ 3*10^8 }{2.25*10^8} \\\\n = 1.33$

- The index of refraction of the liquid is n = 1.33 equivalent to that of water.

8 0

3 years ago

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Many people drink 2 cans of coke each day. If each can has 39 grams of sugar, how many pounds of sugar is consumed each week? Gi

trasher [3.6K]

Answer:

1.20372

Explanation: start with 39 times 2 for how much grams each day and then multiply that by 7 then the convert grams into pounds

5 0

3 years ago

What is nucleic acid

Alekssandra [29.7K]

like dioxyribonucleic acid? if so then that's DNA

8 0

3 years ago

Suppose that during a storm the force of the wind blowing against a skyscraper can be expressed by the vector , where each measu

Andrei [34K]

Answer:

Here we do not have the vector, but I will try to give a kinda general solution to this type of problem.

If the vector is written as (a, b, c) we have that the force in the x-axis is of a Newtons, in the y-axis is of b Newtons, and in the z-axis is of c Newtons.

Then, we can calculate the total magnitude of this force as:

F = √( a^2 + b^2 + c^2)

wich gives us the total magnitude of the force, but not a direction or anything like that, this is just a scalar.

3 0

3 years ago

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Problem 13.175 A 1-kg block B is moving with a velocity v0 of magnitude as it hits the 0.5-kg sphere A, which is at rest and han

Svetradugi [14.3K]

Explanation:

Mass of the Block, Mb = 1.0 kg Initial Velocity of Block, Vb = 2.0 m/s

Mass of the Ball, Ma = 0.5 kg Coefficient of Kinetic Friction, μ = 0.6

Coefficient of Restitution, e = 0.8 Gravity = 9.81 m/s^2

Sum of the forces of the X-axis components and Y-axis components are:

∑ Fx = Ff = Mb × a

Equation for frictional force,

Ff = μ × N

∑ Fy = N - mb × g = 0

Note:

N = mb × g

Therefore, to solve for the acceleration, we have:

μ × Mb × g = Mb × a

a = μ × g

= 0.6 × 9.81

= 5.88 m/s^2

Therefore, ratio of velocities using the coefficient of restitution, e:

e = (Vb2 – Va1)/ (Va – Vb)

Note: Va = zero (initially at rest)

Va2 – Vb2 = 0.8 × ( 0 - 2 m/s)

Vb2 – Va2 = -1.6 m/s

Vb2 = a2 – 1.6

Using Conservation of Momentum Equation:

Ma × Va + Mb × Vb = Ma × Va2 + Mb × Vb2

0 + 1kg × 2 m/s = 0.5 kg × Va2 + 1 kg × Vb2

Vb2 = 2 - 0.5 × Va2

Substitute in Vb2,

1.5 × Va2 = 3.6

Va2 = 2.4 m/s

Vbs = 0.8 m/s

.

mgh = 0.5 × Mv2

h = v2/ 2g

h = 0.294 m

B.

Using equation of motion,

Vf^2 = Vo^2 + 2a × S

Given:

Vf = 0 m/s

a = 5.88 m/s^2

0 = 0.82 + 2(5.88) × ΔS

Δx = 0.0544 m

4 0

3 years ago