Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
From the question we are told that
The center of gravity of the plane to its nose is 
The distance of the front wheel of the plane to its nose is 
The distance of the main wheel of the plane to its nose is 
At equilibrium the Torque about the nose of the airplane is mathematically represented as

Where m is the mass of the airplane
is the weight of the airplane supported by the main wheel
So

Substituting values
Now the weight supported at the frontal wheel is mathematically evaluated as

Substituting values
Now the weight of the airplane is = mg
Thus percentage of this weight supported by the front wheel is
19.82 %
well, you divide 4 by 5, so .8
.8 of a mile is 4224 feet.
i really hope this helps :)
The brightness of the lamp is proportional to the current flowing through the lamp: the larger the current, the brighter the lamp.
The current flowing through the lamp is given by Ohm's law:

where
V is the potential difference across the lamp, which is equal to the emf of the battery, and R is the resistance of the lamp.
The problem says that the battery is replaced with one with lower emf. Looking at the formula, this means that V decreases: if we want to keep the same brightness, we need to keep I constant, therefore we need to decrease R, the resistance of the lamp.
Answer:large
Explanation:
As the temperature increases, materials with large coefficients of linear expansion increases a lot in size