Answer:
Stellar black holes form when the center of a very massive star collapses in upon itself.
Answer:
70 cm
Explanation:
0.5 kg at 20 cm
0.3 kg at 60 cm
x = Distance of the third 0.6 kg mass
Meter stick hanging at 50 cm
Torque about the support point is given by (torque is conserved)
![0.5(50-20)=0.3(60-50)+0.6x\\\Rightarrow x=\dfrac{0.5(50-20)-0.3(60-50)}{0.6}\\\Rightarrow x=20\ cm](https://tex.z-dn.net/?f=0.5%2850-20%29%3D0.3%2860-50%29%2B0.6x%5C%5C%5CRightarrow%20x%3D%5Cdfrac%7B0.5%2850-20%29-0.3%2860-50%29%7D%7B0.6%7D%5C%5C%5CRightarrow%20x%3D20%5C%20cm)
The position of the third mass of 0.6 kg is at 20+50 = 70 cm
In order to form a real image using a concave mirror, the object must be placed beyond the center of curvature of the mirror. Therefore, the object must be further from the mirror than the focal point. The image that will form will be real, but it will also be inverted and its magnification will be less than 1, meaning it will be smaller than the actual object.
Answer: See below
Explanation:
<u>Given:</u>
Mass of the Mercedes-Benz (m) = 1700 kg
Inclination of the road (θ) = 15.0
<em>The free body diagram is shown in figure attached below</em>
<em />
a) The normal force is equal to the cos component of the weight of the car.
![\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26f%3Dm%20g%20%5Ccos%20%5Ctheta%20%5C%5C%26f%3D1700%20%5Ctimes%209.81%20%5Ctimes%20%5Ccos%2015%20%5C%5C%26f%3D16108.74%20%5Cmathrm%7B~N%7D%5Cend%7Baligned%7D)
b) The static force will be equal to the weight's sin component.
![\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26f%3Dm%20g%20%5Csin%20%5Ctheta%20%5C%5C%26f%3D1700%20%5Ctimes%209.81%20%5Ctimes%20%5Csin%2015%20%5C%5C%26f%3D4316.32%20%5Cmathrm%7B~N%7D%5Cend%7Baligned%7D)