Answer:
qasdddddfghjklkmnbvcxzaqwertyuioikjhgbvfcxdgfcgvhgyjfthdgfcvnbhnjkhbjgcfd b
Logarithmic function.very easy find method 10 log = 1 , 5 log 0.6989700034
Answer: y =1
Step-by-step explanation:
Evaluating the equation for x = 0:
y = 54 (0) + 1
y =1
Answer: X = 15
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
So we want to prove that:

First, simplify √8. This is the same as:

Therefore, our equation is now:

Combine like terms on the left:

The square root of something is the same as taking that number to the one-half power. Thus:

Rewrite:

And we're done!