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3 years ago

In the z-scheme is the initial electron donor and is the final electron acceptor.

Physics

1 answer:

Alenkinab [10]3 years ago

6 0

In the z-scheme, water is the initial electron donor and NADP+ is the final electron acceptor.

<u>Explanation: </u>

It is a process of photosynthesis. It occurs in photosynthetic chemical reaction. The z scheme is basically a term for representing the oxidation and reduction reaction occurring in plants during photosynthesis.

The water present in the chlorophyll pigment donates electrons and become the initial electron donor. Those electrons get transferred to NADP+ and forms NADPH. Thus, water acts as electron donor initially and so the final electron is NADP+.

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H.e.y w.h.o w.a.nt.s t.o t.a.l.k

butalik [34]

Answer:

nope

Explanation:

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3 years ago

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Automobile air bags use the decomposition of sodium azide as their sources of gas for rapid inflation, represented in the reacti

NeTakaya

Answer : The mass of $NaN_3$ required is 71.175 grams.

Explanation :

To calculate the moles of nitrogen gas, we use the equation given by ideal gas :

PV = nRT

where,

P = Pressure of nitrogen gas = 763 torr

V = Volume of the nitrogen gas = 40.0 L

n = number of moles of gas = ?

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = Temperature of helium gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$763torr\times 40.0L=n\times 62.364\text{ L.torr }mol^{-1}K^{-1}\times 298K\\\\n=1.642mol$

Now we have to calculate the moles of $NaN_3$ .

The balanced chemical reaction is:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced chemical reaction, we conclude that

As, 3 moles of $N_2$ produced from 2 moles $NaN_3$

So, 1.642 moles of $N_2$ produced from $\frac{2}{3}\times 1.642=1.095$ moles $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

Molar mass of $NaN_3$ = 65 g/mol

$\text{Mass of }NaN_3=\text{Moles of }NaN_3\times \text{Molar mass of }NaN_3$

$\text{Mass of }NaN_3=1.095mole\times 65g/mole=71.175g$

Therefore, the mass of $NaN_3$ required is 71.175 grams.

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3 years ago

A 3.00-m rod is pivoted about its left end. A force of 7.80 N is applied perpendicular to the rod at a distance of 1.60 m from t

dalvyx [7]

Answer:

The net torque about the pivot is and the answer is 'c'

c. $T_{net}=8.58$

Explanation:

$T=F*d$

The torque is the force apply in a distance so it is the moment so depends on the way to be put it the signs so:

$T_1=F_1*d_1$

$T_1=7.8N*1.6m=12.48N*m$

$T_2=F_2*d_2$

$T_2=2.60N**cos(30)*3.0m$

$T_2= - 3.9 N*m$

Now to find the net Torque is the summation of both torques

$T_{net}=T_1+T_2$

$T_{net}=12.48N-3.9N=8.58N$

8 0

3 years ago

Frame S' passes frame S in the usual way. Two events are simultaneous in S'.

yuradex [85]

Answer:

c)They can also be simultaneous in S if their separation is zero.

Explanation:

By relativity theory, we can say two events when seen from two different reference frames can only be simultaneous when they are at the same space location and occur simultaneously in at least one reference frame, therefore when Frame S′ usually passes Frame S. Two occurrences in S′ are simultaneous, therefore these occurrences can be simultaneous in S when their separation is 0 (that is they are at the same location)

And therefore option c. If their separation is zero, they can also be simultaneous in S.

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3 years ago

When the voltage is

gizmo_the_mogwai [7]

Explanation:

ask to nirajan shrestha

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2 years ago

In the z-scheme ____ is the initial electron donor and ____ is the final electron acceptor.

In the z-scheme is the initial electron donor and is the final electron acceptor.