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horrorfan [7]
2 years ago
13

A horse is trotting along pulling a sleigh through the snow. To move the 225 kg sleigh straight ahead at a constant speed, the h

orse must pull with a force of 123N.
a. What is the net force acting on the sleigh?

b. What is the coefficient of kinetic friction between the sleigh and the snow?
Physics
1 answer:
RoseWind [281]2 years ago
5 0

Answer:

a) The net force acting on the sleigh is zero because it is moving at a constant speed.

b) F_{fr}= \mu mg = F_{pull}, then \mu = \frac{F_{pull}}{mg} = 0.0557.

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Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
den301095 [7]

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, f=0.100Hz

Average wavelength =\lambda=15m

Speed of pendulum, v=30m/s

Wavelength, \lambda'=0.32m

We have to find the average speed and frequency of pendulum.

We know that

Speed,v=\lambda f

Using the formula

Average speed,v=15\times 0.1=1.5m/s

Hence, the average speed =1.5m/s

Frequency, f=\frac{v}{\lambda'}

Using the formula

f=\frac{30}{0.32}

f=93.75Hz

Hence, the frequency of a pendulum=93.75Hz

6 0
2 years ago
Advantages of outsourcing project work may likely include all of the following EXCEPT:
yaroslaw [1]

Answer:

e. Reduced conflict.

Explanation:

Outsourcing is a tool that allows you to hire a provider outside the company for the execution of secondary activities, such as cleaning or mail, or covering other areas of the company, such as financial or accounting systems or the human resources area

- Advantages of Outsourcing

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- Transformation of fixed costs into variables

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3 0
3 years ago
A tradesman sharpens a knife by pushing it with a constant force against the rim of a grindstone. The 30-cm-diameter stone is sp
Lorico [155]

Answer:

a. 0.21 rad/s2

b. 2.205 N

Explanation:

We convert from rpm to rad/s knowing that each revolution has 2π radians and each minute is 60 seconds

200 rpm = 200 * 2π / 60 = 21 rad/s

180 rpm = 180 * 2π / 60 = 18.85 rad/s

r = d/2 = 30cm / 2 = 15 cm = 0.15 m

a)So if the angular speed decreases steadily (at a constant rate) from 21 rad/s to 18.85 rad/s within 10s then the angular acceleration is

\alpha = \frac{\Delta \omega}{\Delta t} = \frac{21 - 18.85}{10} = 0.21 rad/s^2

b) Assume the grind stone is a solid disk, its moment of inertia is

I = mR^2/2

Where m = 28 kg is the disk mass and R = 0.15 m is the radius of the disk.

I = 28*0.15^2/2 = 0.315 kgm^2

So the friction torque is

T_f = I\alpha = 0.315*0.21 = 0.06615 Nm

The friction force is

F_f = T_f/R = 0.06615 / 0.15 = 0.441 N

Since the friction coefficient is 0.2, we can calculate the normal force that is used to press the knife against the stone

N = F_f/\mu = 0.441/0.2 = 2.205 N

7 0
3 years ago
Can you give me the definition of sound wave
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A sound wave is a wave of compression and rarefaction, by which sound is propagated in an elastic medium such as air.

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Answer:

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