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3 years ago

How many faces does a right rectangular prism have if it has 8 vertices and 12 edges?

Mathematics

2 answers:

Ganezh [65]3 years ago

5 0

Answer:

Step-by-step explanation:

I think

Rzqust [24]3 years ago

5 0

Vas happenin!!

A rectangular prism has 4 faces

So A is correct

Hope this helps

-Zayn Malik

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One leg of an isosceles right triangle measures 5 inches. Rounded to the nearest tenth, what is the approximate length of the hy

Komok [63]

Since it is isosceles right triangle, both legs = 5 inches.

using pythagoras theorem,

hypotenuse^2 = 5^2 +5^2 = 25+25 = 50
taking square root on both sides,
hypotenuse = sqrt 50 = 5 sqrt 2 or 7.071

rounded to nearest tenth,
length of hypotenuse is 7.1 inches.

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3 years ago

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lisabon 2012 [21]

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3 years ago

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What is the perimeter of triangle PQR? Show your work.

xxMikexx [17]

Answer:

The perimeter of triangle PQR is 17 ft

Step-by-step explanation:

Consider the triangles PQR and STU

1. PQ ≅ ST = 4 ft (Given)

2. ∠PQR ≅ ∠STU (Given)

3. QR ≅ TU = 6 ft (Given)

Therefore, the two triangles are congruent by SAS postulate.

Now, from CPCTE, PR = SU. Therefore,

$3y-2=y+4\\3y-y=4+2\\2y=6\\y=\frac{6}{2}=3$

Now, side PR is given by plugging in 3 for 'y'.

PR = 3(3) - 2 = 9 - 2 = 7 ft

Now, perimeter of a triangle PQR is the sum of all of its sides.

Therefore, Perimeter = PQ + QR + PR

= (4 + 6 + 7) ft

= 17 ft

Hence, the perimeter of triangle PQR is 17 ft.

7 0

4 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$