GUYS PLEASE HELP ME OMG EVERYONE KEEPS SKIPPING:(((
1 answer:
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Comment
By similar triangles it can be shown that AD^2 = AB*AC
If you want the proof, Google tangents and secants of a circle.
Find
So we want
AB
Givens
AD = 16
BC = 9
AB = ??
CA = CB + AB
CA = 9 + AB
Formula
AB * (AB + BC) = AD^2
Sub and Solve
AB*(AB + 9) = 16^2
AB*(AB + 9) = 256 Remove the brackets.
AB^2 + 9AB = 256 Subtract 256 from both sides.
AB^2 + 9AB - 256 = 0
You can only do this either with a graph or the quadratic formula. I'll get the graph for you. You can made these yourself at Desmos.
x = [-b +/- sqrt(b^2 - 4ac)] / (2a)
a = 1
b = 9
c = -256
Answer
When you substitute these into the quadratic formula, you get
x1 = 12.12 and
x2 = -21.12
x2 is meaningless. The solution is
x = 12.12
Comment
But that's not your question. Your question is what is this rounded to the nearest 1/10th? That's a fancy way of saying round to the first decimal place. Since the hundredth place (or second place) is 2, 12.12 rounds to 12.1
The answer is
x = 12.1 <<<<< answer.
By similar triangles it can be shown that AD^2 = AB*AC
If you want the proof, Google tangents and secants of a circle.
Find
So we want
AB
Givens
AD = 16
BC = 9
AB = ??
CA = CB + AB
CA = 9 + AB
Formula
AB * (AB + BC) = AD^2
Sub and Solve
AB*(AB + 9) = 16^2
AB*(AB + 9) = 256 Remove the brackets.
AB^2 + 9AB = 256 Subtract 256 from both sides.
AB^2 + 9AB - 256 = 0
You can only do this either with a graph or the quadratic formula. I'll get the graph for you. You can made these yourself at Desmos.
x = [-b +/- sqrt(b^2 - 4ac)] / (2a)
a = 1
b = 9
c = -256
Answer
When you substitute these into the quadratic formula, you get
x1 = 12.12 and
x2 = -21.12
x2 is meaningless. The solution is
x = 12.12
Comment
But that's not your question. Your question is what is this rounded to the nearest 1/10th? That's a fancy way of saying round to the first decimal place. Since the hundredth place (or second place) is 2, 12.12 rounds to 12.1
The answer is
x = 12.1 <<<<< answer.
For this case we must solve the following equation:
If we apply cubic root to both sides of the equation, then we eliminate the exponent on the left side:
That is the exact solution of the equation. Its decimal solution is given by:
ANswer:
The solution to the equation is
Solving <u>the quadratic equation</u>, it is found that the number of teams is <u>greater than 1000</u> after 3.1 years.
The <u>number of teams after x years </u>is given by:
Initially, there are T(0) = 236 teams. If will 1000 be when T(x) = 1000, thus:
Which has coefficients , then:
We want the positive root, so the number of teams is greater than 1000 after 3.1 years.
A similar problem is given at brainly.com/question/10489198