1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cestrela7 [59]
2 years ago
7

Jerry deposited 20,000 on an investment that will give 1,750 for every year that his money stays in the account. How much money

will he have in his account by the end of the year 8? with solutions​
Mathematics
1 answer:
lesya692 [45]2 years ago
3 0

Answer:

$34,000

Step-by-step explanation:

Jerry will get $1,750 for every year that his money stays in the account thus for 8 years he will get:

8*1,750 = $14,000

Together with the deposited money:

$20,000 + $14,000 = $34,000

By the end of year 8 there will be $34,000 of Jerry's account.

You might be interested in
Rylan paid a total of $2,961.00, including principal and interest, over an 11-month period, to pay off his credit card. Choose t
bonufazy [111]

Answer: I would go with C

Step-by-step explanation: if correct please mark brainliest

3 0
2 years ago
Mrs.Brown gives two tests to her class. 30% of the class passed both tests and 45% of the class passed the first test. What perc
viktelen [127]

Answer:

25%

Step-by-step explanation:

100%-30%=70%

70%-45%=25%

7 0
3 years ago
A recipe for chicken marinade says, "Mix 3 parts oil with 2 parts soy sauce and 1 part orange juice." If you need 42 cups of mar
iVinArrow [24]

Answer:

We will use;

21 parts oil

14 parts soy sauce

7 parts Orange

Step-by-step explanation:

We can have all of these as a ratio

That would be;

3 + 2 + 1 = 6

For oil

3/6 * 42 = 21 parts of oil

For Soy sauce

= 2/6 * 42 = 14 parts soy sauce

For Orange

= 1/6 * 42 = 7 parts orange juice

5 0
2 years ago
Read 2 more answers
The area of a rhombus is 90 square inches. If the longer diagonal measures 18 inches, what is the length of the shorter diagonal
lorasvet [3.4K]
10 Inches

A = p q / 2

p = diagonal 1
q = diagonal 2

2A / q = p

Solve for p
180/18 = 10
5 0
3 years ago
Mystery Boxes: Breakout Rooms
ollegr [7]

Answer:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

Step-by-step explanation:

Given

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}

Required

Fill in the box

From the question, the range is:

Range = 60

Range is calculated as:

Range =  Highest - Least

From the box, we have:

Least = 1

So:

60 = Highest  - 1

Highest = 60 +1

Highest = 61

The box, becomes:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question:

IQR = 20 --- interquartile range

This is calculated as:

IQR = Q_3 - Q_1

Q_3 is the median of the upper half while Q_1 is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}

<u>Upper half</u>

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

The quartile is calculated by calculating the median for each of the above halves is calculated as:

Median = \frac{N + 1}{2}th

Where N = 7

So, we have:

Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th

So,

Q_3 = 4th item of the upper halves

Q_1= 4th item of the lower halves

From the upper halves

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

<u></u>

We have:

Q_3 = 32

Q_1 can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

IQR = Q_3 - Q_1

Where Q_3 = 32 and IQR = 20

So:

20 = 32 - Q_1

Q_1 = 32 - 20

Q_1 = 12

So, the lower half becomes:

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}

From this, the updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question, the median is:

Median = 22 and N = 14

To calculate the median, we make use of:

Median = \frac{N + 1}{2}th

Median = \frac{14 + 1}{2}th

Median = \frac{15}{2}th

Median = 7.5th

This means that, the median is the average of the 7th and 8th items.

The 7th and 8th items are blanks.

However, from the question; the mode is:

Mode = 18

Since the values of the box are in increasing order and the average of 18 and 18 do not equal 22 (i.e. the median), then the 7th item is:

7th = 18

The 8th item is calculated as thus:

Median = \frac{1}{2}(7th + 8th)

22= \frac{1}{2}(18 + 8th)

Multiply through by 2

44 = 18 + 8th

8th = 44 - 18

8th = 26

The updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question.

Mean = 26

Mean is calculated as:

Mean = \frac{\sum x}{n}

So, we have:

26= \frac{1 + 2nd + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 12th + 58 + 61}{14}

Collect like terms

26= \frac{ 2nd + 12th+1 + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 58 + 61}{14}

26= \frac{ 2nd + 12th+304}{14}

Multiply through by 14

14 * 26= 2nd + 12th+304

364= 2nd + 12th+304

This gives:

2nd + 12th = 364 - 304

2nd + 12th = 60

From the updated box,

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

We know that:

<em>The 2nd value can only be either 2 or 3</em>

<em>The 12th value can take any of the range 33 to 57</em>

Of these values, the only possible values of 2nd and 12th that give a sum of 60 are:

2nd = 3

12th = 57

i.e.

2nd + 12th = 60

3 + 57 = 60

So, the complete box is:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

6 0
2 years ago
Other questions:
  • Mindy spent $6.24 fir a new binder,$1.95 for a notebook,and $5.59 for a new pack of her favorite mechanical pencils. About how m
    6·1 answer
  • If DH= 9.5 find FH and DF
    15·1 answer
  • 3k - 2 &gt; 2 4 or -3k + 9 &gt; 27
    10·1 answer
  • A science class is tracking the progress of plant growth. The class starts the experiment with a plant five centimeters high. Th
    11·2 answers
  • Which best describes the range of the function f(x) = 2/3(6)x after it has been reflected over the x-axis?
    9·1 answer
  • Solve each inequality and graph its solution. Can you guys solve all three please. This is do soon so please help!
    14·1 answer
  • Write an equation of the line that passes through a pair of points: (2, 3), (4, -2)
    6·1 answer
  • The type of match to use in a Vlookup() function to assess the resort fee as a possible additional cost for a particular room is
    11·1 answer
  • Find the product of 3/5 x 7/4. Then, write another pair of factors with the same product
    15·2 answers
  • The z value for a 97. 8% confidence interval estimation is.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!