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2 years ago

5

You have discovered a planet that is one-quarter the radius of Earth (Rp = 1/4R⊕) and one-half as massive (Mp = 1/2M⊕). How does

the gravity on the surface of this planet compare to the gravity on the surface of Earth (Fgp = XFg⊕)?

1 answer:

ExtremeBDS [4]2 years ago

4 0

It's 8 times as much as before.

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3 years ago

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Elena-2011 [213]

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a)
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4 years ago

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trasher [3.6K]

Answer:

$\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2$

Explanation:

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Series combination is

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Now dividing series equivalent resistance by parallel resistance gives us

$\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2$ .

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3 years ago

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professor190 [17]

Answer:

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3 years ago

Read 2 more answers