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harkovskaia [24]
3 years ago
5

A transmitter generates a 15-dBm signal and is connected to an antenna using a cable that introduce 2 dB of loss. The cable has

two connectors, one at each end, that intro-duce a loss of 2 dB each. What is the signal level at the input of the antenna in dBm and milliwatts?
Physics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

9 dBm or 7.94 mW

Explanation:

As per the question:

Signal generated by the transmitter, x_{T} = 15 dBm

Loss by the antenna, L = 2 dB

No. of connectors, n = 2

Loss by each connector, l = 2 dB

Now,

The signal level at the input of the antenna:

P = x_{T} - L - nl = 15 - 2 - 2\times 2 = 9\ dBm

Now, the signal level at the input in milliwatt:

P = \frac{10^{\frac{P(in\ dBm)}{10}}}{1000}

P = \frac{10^{\frac{9}{10}}}{1000} = 7.94\ mW

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Two sinusoidal waves with identical wavelengths and amplitudes travel in opposite directions along a string with a speed of 10 c
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Answer:

The wave length of the string = 10 cm or 0.1 m

Explanation:

Wave: A wave can be defined as a disturbance, which travels through a medium and transfer energy from one point to another, without causing any permanent displacement of the medium itself.

 The velocity, frequency and wavelength of a wave is related as shown,

v = λf ........................ Equation 1

Where v = velocity of the wave, λ = wave length, f = frequency.

λ = v/f ..................... Equation 2.

Given: v = 10 cm/s,

T = 2t, where t = 0.5 s, (This is half of one cycle)  

T = 2×0.5 = 1 s,

But T = 1/f = 1/1 = 1 Hz.

Substituting these values into equation 2

λ  = 10(1)

λ  = 10 cm. or 0.1 m

Thus the wave length of the waves = 10 cm or 0.1 m

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3 years ago
What is the fault-current circuit breaker? Describe its function.
Nimfa-mama [501]

Answer:

A circuit breaker is a switching mechanism that interrupts the current that is irregular or fault. It is a mechanical system that interferes with high magnitude (fault) current flow and also performs a transfer operation. Hope this helps :)

Explanation:

4 0
3 years ago
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What is the approximate weight of a 20-kg cannonball on earth?
disa [49]
The weight of an object is taken to be the force on the object due to gravity. The weight ( W ) is the product of the mass ( m ) of the object and the magnitude of the gravitational acceleration ( g ).
On Earth: g = 9.81 m/s²
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W = m · g = 20 kg · 9.81 m/s² = 196.2 N
6 0
3 years ago
Three masses are located in the x-y plane as follows: a mass of 6 kg is located at (0 m, 0 m), a mass of 4 kg is located at (3 m
Natali [406]
<h2>Answer:</h2>

D. (1m, 0.5m)

<h2>Explanation:</h2>

The center of mass (or center of gravity) of a system of particles is the point where the weight acts when the individual particles are replaced by a single particle of equivalent mass. For the three masses, the coordinates of the center of mass C(x, y) is given by;

x = (m₁x₁ + m₂x₂ + m₃x₃) / M       ----------------(i)

y = (m₁y₁ + m₂y₂ + m₃y₃) / M       ----------------(ii)

Where;

M = sum of the masses

m₁ and x₁ = mass and position of first mass in the x direction.

m₂ and x₂ = mass and position of second mass in the x direction.

m₃ and x₃ = mass and position of third mass in the x direction.

y₁ , y₂ and y₃ = positions of the first, second and third masses respectively in the y direction.

From the question;

m₁ = 6kg

m₂ = 4kg

m₃ = 2kg

x₁ = 0m

x₂ = 3m

x₃ = 0m

y₁ = 0m

y₂ = 0m

y₃ = 3m

M = m₁ + m₂ + m₃ = 6 + 4 + 2 = 12kg

Substitute these values into equations (i) and (ii) as follows;

x = ((6x0) + (4x3) + (2x0)) / 12

x = 12 / 12

x = 1 m  

y = (6x0) + (4x0) + (2x3)) / 12

y = 6 / 12

y = 0.5m

Therefore, the center of mass of the system is at (1m, 0.5m)

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almond37 [142]

Answer: When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. If a balloon is not rubbed with the wool cloth, it has an equal amount of negative to positive charges, so it will attract to a rubbed balloon.

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