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harkovskaia [24]
3 years ago
5

A transmitter generates a 15-dBm signal and is connected to an antenna using a cable that introduce 2 dB of loss. The cable has

two connectors, one at each end, that intro-duce a loss of 2 dB each. What is the signal level at the input of the antenna in dBm and milliwatts?
Physics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

9 dBm or 7.94 mW

Explanation:

As per the question:

Signal generated by the transmitter, x_{T} = 15 dBm

Loss by the antenna, L = 2 dB

No. of connectors, n = 2

Loss by each connector, l = 2 dB

Now,

The signal level at the input of the antenna:

P = x_{T} - L - nl = 15 - 2 - 2\times 2 = 9\ dBm

Now, the signal level at the input in milliwatt:

P = \frac{10^{\frac{P(in\ dBm)}{10}}}{1000}

P = \frac{10^{\frac{9}{10}}}{1000} = 7.94\ mW

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A 73.9 kg weight-watcher wishes to climb a
Tresset [83]

The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km

<h3>How to determine the energy. </h3>

1 food calorie = 103 calories

Therefore,

991 food calories = 991 × 103

991 food calories = 102073 calories

Multiply by 4.2 to express in joule (J)

991 food calories = 102073 × 4.2

991 food calories = 428706.6 J

<h3>How to determine the height </h3>
  • Energy (E) = 428706.6 J
  • Mass (m) = 73.9 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) =?

E = mgh

Divide both side by mg

h = E / mg

h = 428706.6 / (73.9 × 9.8)

h = 591.95 m

Divide by 1000 to express in km

h = 591.95 / 1000

h = 0.59 Km

Learn more about energy:

brainly.com/question/10703928

7 0
2 years ago
The length of a rectangle is increasing at a rate of 4 cm/s and its width is increasing at a rate of 6 cm/s. When the length is
Fudgin [204]

Answer:

24cm/s

Explanation:

A=L*w

A'=L'*w'

L=13

w=5

L'=4

w'=6

A=?

A'=?

A=L*w

A=13*5

A=65

A'=L'*w'

A'=4*6

A'=24

*the given lengths are just to throw you off*

3 0
3 years ago
A water pump pumps 3 kg of water every second from the bottom of a well to the top of the well 50 m above if the pump used 2000
vesna_86 [32]

watts = work per second.

work is mgh = 3x10x50=1500

watts out = 1500

Watts used = 2000

eff=1500/2000=75%


8 0
3 years ago
A small rubber ball is launched by a compressed-air cannon from ground level with an initial speed of 11.8 m/s directly upward.
Fantom [35]

Answer:

7.09683 m

1.20285 s

2.4057 s

11.8 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² (negative up, positive down)

From equation of motion we have

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-11.8^2}{2\times -9.81}\\\Rightarrow s=7.09683\ m

The maximum height above the ground that the ball reaches is 7.09683 m

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-11.8}{-9.81}\\\Rightarrow t=1.20285\ s

Time taken to go up is 1.20285 s it will take the same time to come down so total time taken to reach the ground after it is shot is 1.20285+1.20285 = 2.4057 s

v=u+at\\\Rightarrow v=0+9.81\times 1.20285\\\Rightarrow v=11.8\ m/s

The velocity just before it hits the ground is 11.8 m/s

6 0
2 years ago
Tudy the images about geologic time.
Inessa [10]

Answer:

The first flowering plants appeared in the Mesozoic era, not the Paleozoic era.

Explanation:

The Mesozoic era was an era where numerous organisms started to develop in very unique and more advanced ways, both the animals and the plants. In the last period of the Mesozoic, the Cretaceous, the first flowering plants started to appear on the scene. This was revolutionary trait of the plants, and soon these plants started to occupy more and more space and became one of the dominant organisms on the planet. Other important evolution that took place in this period are the appearance of the dinosaurs and the mammals, both becoming the dominant animals on the planet, first the dinosaurs, after that the mammals.

8 0
3 years ago
Read 2 more answers
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