What type of rock forms most often near an active volcano?
2 answers:
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Answer:
<em>The magnetic field is 0.0857 T.</em>
Explanation:
The electrons orbit the magnetic field with a centripetal force equal to
F =
also, the force on an electron in a magnetic field is gotten as
F = Bqv
equating this two equations give
= Bqv
mv/r = Bq
where m is the mass of the electron = 9.11 x 10^-31 kg
v is the the linear speed of the electron
B is the magnetic field on the electron
r is the radius of the orbital movement
q is the charge on an electron = 1.602 x 10^-19 C
but, the linear speed v = ωr
where ω is the angular speed of the electron
substituting into equation above, we have
mωr/r = Bq
which reduces to
mω = Bq
finally, w know that the angular speed is related to the frequency of the electron by
ω = 2πf
we then finally have
2mπf = Bq
where f is the frequency emitted by the electron = 2.4 GHz = 2.4 x 10^9 Hz
substituting values into the equation, we have
2 x 9.11 x 10^-31 x 3.142 x 2.4 x 10^9 = B x 1.602 x 10^-19
B = (1.3734 x 10^-20)/(1.602 x 10^-19) = <em>0.0857 T</em>
= <em>85.7 mT</em>
Answer:
The speed of wave in the second string is 55.3 m/s.
Explanation:
Given that,
Speed of wave in first string= 58 m/s
We need to calculate the wave speed
Using formula of speed for first string
...(I)
For second string
...(II)
Divided equation (II) by equation (I)
Here, Tension is same in both string
So,
The linear density of the second string
Now, Put the value of linear density of second string
Hence, The speed of wave in the second string is 55.3 m/s.