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Schach [20]
3 years ago
15

Need help! Thanks for whoever answers.

Physics
2 answers:
kotegsom [21]3 years ago
7 0

Hi there!

Finding the time taken to land deals with the VERTICAL motion of the object, so we can disregard the horizontal velocity.

Use the simplified kinematic equation:

t = √2h/g

Plug in given values. Let g = 9.8 m/s²

t = √2(75)/9.8 = 3.91 sec

Hunter-Best [27]3 years ago
5 0

Answer:

2021 + 100000000

Explanation:

i o g kk ybb

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  • Ø=37°
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#A

\\ \rm\Rrightarrow H_{max}=\dfrac{u^2sin^2\theta}{2g}

\\ \rm\Rrightarrow H_{max}=\dfrac{20^2(sin37)^2}{2(10)}

\\ \rm\Rrightarrow H_{max}=\dfrac{400sin^237}{20}

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#B

\\ \rm\Rrightarrow R=\dfrac{u^2sin2\theta}{g}

\\ \rm\Rrightarrow R=\dfrac{20^2sin74}{10}

\\ \rm\Rrightarrow R=40sin74

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#C

\\ \rm\Rrightarrow T=\dfrac{2usin\theta}{g}

\\ \rm\Rrightarrow T=\dfrac{2(20)sin37}{10}

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\\ \rm\Rrightarrow T=2.4s

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\\ \rm\Rrightarrow v=u-gt

\\ \rm\Rrightarrow v=20-10(2.4)

\\ \rm\Rrightarrow v=20-24

\\ \rm\Rrightarrow v=-4m/s

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